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Masja [62]
3 years ago
12

The circumference of circle 1 is 16 pi units. The circumference of circle 2 is 6 pi units. Which of the following is true about

the area of the circles?
Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

Area of Circle 1=>64(pi) units^2

Area of Circle 2=>9(pi) units^2

Step-by-step explanation:

Circumference=2(pi)r

Circle 1: 2(pi)r=16(pi)

Divide by 2(pi) on both sides

r=8 units

Area=(pi)r^2

Area of circle 1=>(pi)*(8^2)

Area of Circle 1=>64(pi) units^2

Circle 2: 2(pi)r=6(pi)

Divide by 2(pi) on both sides

r=3 units

Area=(pi)r^2

Area of circle 2=>(pi)*(3^2)

Area of Circle 2=>9(pi) units^2

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The equation C = 20n + 35 represents the relationship between the cost of school volleyball uniforms, C, in dollars, and the num
Margaret [11]

The equation represent a linear relation with the y-intercept

representing the amount of initial fee.

Correct response:

1. 28 volleyball uniforms

2. Price per uniform

3. Initial flat order fee

4. 10 fewer volleyball uniform

<h3>Methods used for finding the above values</h3>

The given equation that represents the relationship between the cost of school volleyball uniform is; C = 20·n + 35

Where;

C = The uniform costs

n = The number of volleyball uniform ordered

The maximum amount the school has to spend = $600

1. The number of uniforms the school can buy is given by setting C = 600 as follows;

  • C = 20·n + 35

Therefore;

600 = 20·n + 35

20·n = 600 - 35 = 565

n = \dfrac{565}{20} = \mathbf{28.25}

Rounding down to the nearest whole number, we have;

  • The number of uniforms the school can buy, n = <u>28 volleyball uniforms</u>.

2. The number 20 represent the additional cost for each extra uniform, which is the unit cost therefore;

  • 20 represents a <u>$20 price per uniform</u>.

3. The 35 in the equation represents an initial <u>flat fee</u>, such as an

ordering or initial fee, which is fixed.

Therefore;

  • The number 35 represent the <u>fixed cost </u>for producing the uniforms

4. The price per uniform of $30 changes the coefficient of <em>n</em> from 20 to 30 as follows;

C = 30·n + 35

The number of uniforms the school can by with $600 is therefore;

n = \dfrac{600 - 35}{30} = \mathbf{18.8 \overline 3}

Which gives;

The number of uniforms the school can purchase at $30 per uniform is n = 18 volleyball uniforms

The difference in the number of uniforms purchased = 28 - 18 = 10

Therefore;

  • The school can purchase <u>10 fewer uniforms</u> at $30 per uniform

Learn more about linear equations here:

brainly.com/question/10452752

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2 years ago
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