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Zarrin [17]
3 years ago
10

10a^2b^0 for a=–3, b=–8

Mathematics
2 answers:
NeTakaya3 years ago
7 0

Answer:

<h2>90</h2>

Step-by-step explanation:

Substitute a = -3 and b = -8 to the expression 10a²b⁰:

10(-3)²(-8)⁰ = 10(9)(1) = 90

a⁰ = 1 for any real number

Rasek [7]3 years ago
6 0

Answer:

90

Step-by-step explanation:

10a^2b^0

Let a=–3, b=–8

10 (-3)^2 ( -8)^0

10 * 9 *1

90

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Read 2 more answers
1/3(33x +15) - 1/3 ( 21x +18) =10
inn [45]
          ¹/₃(33x + 15) - ¹/₃(21x + 18) = 10
¹/₃(33x) + ¹/₃(15) - ¹/₃(21x) - ¹/₃(18) = 10
                             11x + 5 - 7x - 6 = 10
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