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Ipatiy [6.2K]
3 years ago
6

100 POINTS! PLEASE HELP!

Mathematics
2 answers:
Elena-2011 [213]3 years ago
8 0

y=-4x+5

Step-by-step explanation:

Step 1:  Find the slope

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{13-5}{-2-0}

m=-\frac{8}{2}

m=-4

Step 2:  Use point slope form

(y-5) = -4(x-0)

y-5 + 5=-4x + 5

y=-4x+5

lesantik [10]3 years ago
4 0

Answer:

y=-4x+5

Step-by-step explanation:

<u>Step 1:  Find the slope</u>

<u />m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{13-5}{-2-0}

m=-\frac{8}{2}

m=-4

<u>Step 2:  Use point slope form</u>

<u />(y-5) = -4(x-0)

y-5 + 5=-4x + 5

y=-4x+5

Answer:  y=-4x+5

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Kyle divided two numbers in scientific notation using the interactive calculator and found a solution of 3.5E4. If the numerator
Maru [420]

Answer:

a=2, b=5

Step-by-step explanation:

Let

n -----> the denominator

we have

3.5*10^4=\frac{7*10^9}{n}

Solve for n

That means -----> isolate the variable n

Multiply by n both sides

3.5*10^4(n)=7*10^9

Divide by 3.5*10^4 both sides

n=\frac{7*10^9}{3.5*10^4}=(\frac{7}{3.5})(\frac{10^9}{10^4})=2*10^5

therefore

a=2, b=5

5 0
3 years ago
Read 2 more answers
If the ratio of the sides of two squares is 3:1, what is the ratio of their perimeters?
Anvisha [2.4K]

Answer:

Ratio of the perimeters =3:1

Step-by-step explanation:

We have given that : Ratio of the sides of two squares is 3:1

To find : Ratio of their perimeters

Solution : Let the length of the sides are 3:1 = 3x : x

                  Formula of perimeter of square = 4(side)

Using the formula ,

Perimeter of 1 square = 4×3x= 12x

Perimeter of 2 square = 4×x= 4x

Ratio of the perimeter of 1 square and 2 square = 12x : 4x

                                                                                 = 3 : 1


8 0
3 years ago
Explain how you can tell whether the sum of two integers is positive or negative, before adding them.
julsineya [31]

Answer:

The sum of any integer and its opposite is equal to zero. adding two negative integers always yields a negative sum. To find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract these values.

7 0
3 years ago
Read 2 more answers
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
In the diagram below, assume that all points are given in rectangular coordinates. Determine the polar coordinates for each poin
Korolek [52]

Step-by-step explanation:

We have cartisean points. We are trying to find polar points.

We can find r by applying the pythagorean theorem to the x value and y values.

r  {}^{2} =  {x}^{2}  +  {y}^{2}

And to find theta, notice how a right triangle is created if we draw the base(the x value) and the height(y value). We also just found our r( hypotenuse) so ignore that. We know the opposite side and the adjacent side originally. so we can use the tangent function.

\tan(x)  =  \frac{y}{x}

Remeber since we are trying to find the angle measure, use inverse tan function

\tan {}^{ - 1} ( \frac{y}{x} )  =

Answers For 2,5

{2}^{2}  +  {5}^{2}  =  \sqrt{29}  = 5.4

So r=sqr root of 29

\tan {}^{ - 1} ( \frac{5}{2} )  = 68

So the answer is (sqr root of 29,68).

For -3,3

{ -3 }^{2}  +  {3}^{2}  =  \sqrt{18}  = 3 \sqrt{2}

\tan {}^{ - 1} ( \frac{3}{ - 3} )  =  - 45

Use the identity

\tan(x)  =  \tan(x + \pi)

So that means

\tan(x)  = 135

So our points are

(3 times sqr root of 2, 135)

For 5,-3.5

{5}^{2}  +  {3.5}^{2}  =  \sqrt{37.25}

\tan {}^{ - 1} ( \frac{ - 3.5}{ - 5} )  = 35

So our points are (sqr root of 37.25, 35)

For (0,-5.4)

{0}^{2}  +  { - 5.4}^{2}  = \sqrt{}  29.16 = 5.4

So r=5.4

\tan {}^{ - 1}  (0)  = undefined

So our points are (5.4, undefined)

4 0
3 years ago
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