Answer:
Step-by-step explanation:
Hello!
The variable of interest, X: height of women at a college, has an approximately normal distribution with mean μ= 65 inches and standard deviation σ= 1.5 inches.
You need to look for the value of height that marks the bottom 20% of the distribution, i.e. the height at the 20th percentile of the normal curve, symbolically:
P(X≤x₀)= 0.20
To know what value of height belongs to the 20% of the distribution, you have to work using the standard normal distribution and then reverse the standardization with the population mean and standard deviation to reach the value of X. So the first step is to look for the Z-value that accumulates 20% of the distribution:
P(Z≤z₀)=0.20
z₀= -0.842
z₀= (x₀-μ)/σ
z₀*σ= (x₀-μ)
x₀= (z₀*σ)+μ
x₀= (-0.842*1.5)+65
x₀= 63.737 inches
I hope it helps!
12x12 + 12x12 = 288 = root of 288= 16.97
So the easiest way to do this problem is to put your equation in linear form, meaning y = the rest of the equation.
I'm going to show the work to do that below:
2x - y = 4
-2x -2x (Here I am subtracting 2x)
- y = 4 - 2x
(-1)(- y) = (-1)(4 - 2x) (Now I'm multiplying both sides by -1 to make y positive)
y = 2x - 4 (And just for neat purposes I'm going to put the 2x in front of the 4)
Now you have your equation ( y=2x-4 ) and you're ready to put it on the points of your graph.
Start on the point (0, -4) to represent the y axis.
y = 2x - 4
Then, your rise (2) over your run (1)
so your coordinates for a line will be:
(0, -4) (-2, 1) (1, 0)
You only need to plot these three to connect your line.
I appologize for my lack of visuals i understand this might be confusing, however if you have any further questions feel free to let me know!
Answer:
At 10:30 A.M.
Step-by-step explanation:
A college offers shuttle service from Dickson Hall or Lot B to its campus quad.
At 9:10 A.M the first shuttle leaves from their locations for the campus.
If the shuttles leave from Lot B every 10 minutes and leave from Dickson Hall every 12 minutes, then both the shuttles will leave their origin at the same time after 60 minutes.
This is because 60 is the smallest multiple of 10 and 12 which is common for them.
Therefore, 10:30 A.M. is the next time when both shuttles will depart for the campus at the same time. (Answer)
Step-by-step explanation:
6+(-18)+54+(-162)
6-18+54-162
-12+(-108)
-12-108
= -120
