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Andrej [43]
3 years ago
9

The table below shows the number of kilometers Jessica ran this weekend.

Mathematics
2 answers:
monitta3 years ago
6 0

Answer:

5

Step-by-step explanation:

3+4=7

7-2=5

If you need a better explanation, comment.

damaskus [11]3 years ago
6 0
The answer is 5. I think its 5.
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10x + 7y = –8<br> 7x + 7y = –14
Georgia [21]

Answer:

(2, - 4 )

Step-by-step explanation:

Given the 2 equations

10x + 7y = - 8 → (1)

7x + 7y = - 14 → (2)

Subtract (2) from (1) term by term to eliminate y

(10x - 7x) + (7y - 7y) = - 8 - (- 14) , that is

3x = 6 ( divide both sides by 3 )

x = 2

Substitute x = 2 into either of the 2 equations and solve for y

Substituting into (1)

10(2) + 7y = - 8

20 + 7y = - 8 ( subtract 20 from both sides )

7y = - 28 ( divide both sides by 7 )

y = - 4

solution to the system of equations is (2, - 4 )

4 0
3 years ago
Which function is best represented by this graph?
zalisa [80]

Answer:

B- y=\frac{1}{4}x-2

Step-by-step explanation:

To look at the slope you can count over four and then up one and its at the next point.

Also, the place on the y-axis is at -2

So, b makes the most since :)

Hope this helps :) (if it does, brainliest??)

7 0
3 years ago
What is the volume of the plastic rocket???
Snezhnost [94]

Answer:

A) 151 in³ or 151 cubic inches

Step-by-step explanation:

Volume of rocket = Volume of Cylinder + Volume of Cone

Step 1

Find the volume of the cylinder

Volume of a cylinder = πr²h

r = Diameter/2

= 5/2 = 2.5 inches

h = 6 inches

Hence,

π × 2.5² × 6

= 117.81 cubic inches

Step 2

Find the volume of the cone

Volume of a cone =1/3 πr²h

h = 11 inches - 6 inches

= 5 inches

r = 2.5 inches

Hence,

1/3 × π × 2.5² × 5

= 32.72 cubic inches

Therefore:

Volume of rocket = Volume of Cylinder + Volume of Cone

= 117.81 cubic inches + 32.72 cubic inches

= 150.53 cubic inches

Approximately to the nearest inch = 151 in³ or 151 cubic inches

Option A is correct

7 0
3 years ago
PLEASE HELP!!!
tatuchka [14]
Asked and answered elsewhere.
brainly.com/question/10629871

How do you calculate it? You start by expressing the density in the units you have. Then you multiply by appropriate conversion factors to get to the units you want. Treat units as though they were any other variable. A value cancels that appears in both the numerator and denominator of a fraction.

\dfrac{56.15\,kg}{0.222\,hh}\cdot \dfrac{1000\,g}{1\,kg}\cdot \dfrac{1\,pw}{1.55\,g}\cdot \dfrac{1\,hh}{238.5\,L}\cdot \dfrac{9.091\,L}{1\,pk}\\\\=\dfrac{56.15\cdot 1000\cdot 9.091\,pw}{0.222\cdot 1.55\cdot 238.5\,pk}\\\\ \approx6220\,\frac{pw}{pk}
5 0
3 years ago
30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 &lt;0
Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}

2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)

\mathrm{Simplify}

-2logx^3-3

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}

-2logx^3-3+3

\mathrm{Simplify}

-2logx^3

Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)

\mathrm{Simplify}

2lx^3og>2\log ^3\left(x\right)-3

\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0

\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\

\mathrm{Simplify}

g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0

Step-by-step explanation:

6 0
3 years ago
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