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2 years ago

The side length of a square is represented by the expression n-15

Mathematics

1 answer:

erik [133]2 years ago

8 0

91819 n-19 +12=092!o

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State the positive values of X for which the production costs at the two sites are equal. Explain how you determined your answer

Shkiper50 [21]

Answer:

Step-by-step explanation:

A(x)=3x^2

B(x)=8x+3

A(x)=B(x)

3x^2=8x+3

3x^2-8x-3=0

factor

(3x+1)(x-3)=0

x-3=0

x=3

3(3^2)=8(3)+3

3(9)=24+3

27=27

8 0

2 years ago

With

Hatshy [7]

<span>y - 2418.6 = 5.9(x - 54)
y - 2418.6 = 5.9x - 318.6
y = 5.9x + 2100
f(x) = 5.9x + 2100 (this is our function)
.
Now we can answer:
What is the weight of the plane with 26 gallons of fuel in its tank?
f(26) = 5.9(26) + 2100 = 2253.4 pounds
(Put me as brainiest!!!! <3)</span>

3 0

3 years ago

Area question. Please help!

vivado [14]

Answer:7

Step-by-step explanation: the corners are half and there is 5 normal squares and 4 half squares so half of 4 is 2 and 5+2=7

7 0

2 years ago

Read 2 more answers

Does anyone know this?

Stels [109]

Every hexagon clearly has 6 sides. Nevertheless, every time you "glue" two hexagons together, you "lose" 2 sides to your count, because the sides where the two hexagons meet are not exterior sides anymore, and so they are not taken into account in our counting.

Also observe that with n hexagons you have n-1 points of contact between hexagons.

Since every hexagon has 6 sides and every gluing point takes away 2 sides, the number of exterior sides with n hexagons is

$s(n)=6n - 2(n-1) = 6n-2n+2=4n+2$

Let's plug some values for n:

$s(1) = 4\cdot 1 + 2 = 4+2 = 6$
$s(2) = 4\cdot 2 + 2 = 8+2 = 10$
$s(3) = 4\cdot 3 + 2 = 12+2 = 14$
$s(4) = 4\cdot 4 + 2 = 16+2 = 18$

You can check that these values are correct by counting the sides on the figure you have.

Finally, we can count the sides of a train with 10 hexagons by plugging n=10 in our formula:

$s(10) = 4\cdot 10 + 2 = 40 + 2 = 42$

Note: the numbers we've given are the number of sides that form the perimeter. So, the actual perimeters are the number of sides multiplied by the length of the side itself: if we let $s$ be the length of the side, the perimeters will be $6s,\ 10s,\ 14s,\ 18s$ for the first 4 trains, and $42s$ for the 10-hexagon train.