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Makovka662 [10]
3 years ago
11

Find the least common multiple of the following polynomials 9(x+2)(2x-1) and 3(x+2)

Mathematics
1 answer:
ololo11 [35]3 years ago
3 0
A common multiple<span> is a number that is a </span>multiple<span> of two or more numbers. The </span>common multiples<span> of 3 and 4 are 0, 12, 24, .... The </span>least common multiple<span> (</span>LCM) of two numbers is the smallest number (not zero) that is amultiple<span> of both.
so to the given </span><span>9(x+2)(2x-1) and 3(x+2)
the LCM would be 9</span>(x+2)(2x-1)
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ABCD is a rectangle ,its diagonals meet at O.If AO = 5x+1 and BO = 4x+9,find the length of the diagonals .(lengths in cm).
Sergeu [11.5K]

Answer:

82 cm

Step-by-step explanation:

In rectangles diagonals are equal and bisect each other

AO = BO

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Subtract 1 from  both sides

5x  = 4x + 9 -1

5x = 4x + 8

Subtract 4x from both the sides

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x = 8

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3 years ago
Find the following ratios. Write each answer as a fraction and as a decimal rounded to four decimal places.
Alona [7]

Answer:

y = 56.6208

Step-by-step explanation:

Given

The attached triangle

Required

Find y

To find y, we make use of the relationship between sides lengths 44 & y and angle 39

The relationship is:

cos(39) = \frac{44}{y}

i.e.

cos(\theta) = \frac{Adjacent}{Hypotenuse}

Make y the subject

y = \frac{44}{cos(39)}

y = \frac{44}{0.7771}

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