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Misha Larkins [42]
1 year ago
14

The mean exam score for the first group of twenty examinees applying for a security job is 35.3 with a standard deviation of 3.6

.
The mean exam score for the second group of twenty examinees is 34.1 with a standard deviation of 0.5. Both distributions are close to symmetric in shape.

Use the mean and standard deviation to compare the scores of the two groups.
Mathematics
1 answer:
babymother [125]1 year ago
6 0

The scores of two groups can be compared using coefficient of variation;

Coefficient of variation (C.V.) = (Standard Deviation/ Mean) × 100%;

For Data set 1;

Standard deviation = 3.6

Mean = 35.3

C.V. = (3.6/35.3) × 100%;

       = 10.19%

For Data set 2;

Standard deviation = 0.5

Mean = 34.1

C.V. = (0.5/34.1) × 100%;

       = 1.46%

To learn more about coefficient of variation, visit: brainly.com/question/24131744

#SPJ9

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Answer:

Using Geometry to answer the question would be the simplest:

Step-by-step explanation:

Remembering the formula for the area of a triangle which is A=\frac12bh. One can then tackle the question by doing the following:

Step 1 Find the y-intercepts

The y-intercepts are found by substituting in x=0.

Which gives you this when you plug it into both equations:

-y=1\\y=-1\\y=8

So the y-intercepts for the graphs are (0,-1)\\, and (0,8) respectively.

Now one has to use elimination to solve the problems by adding up the equations we get:

x-y=1\\2x+y=8\\3x=9\\x=3

Now to solve for the y component substitute:

2(3)+y=8\\y=2

Therefore, the graphs intersect at the following:

(3,2)

Now we have our triangle which is accompanied by the graph.

now to solve it we must figure out how long the base is:

b=8-(-1)\\b=9

The height must also be accounted for which is the following:

h=3

Now the formula can be used:

A=\frac12bh=\frac12(9)(3)=\frac{27}2\ \text{units}^2

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To find the answer:
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Hope it helps!
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Due in 20 mins help pls
kodGreya [7K]

Answer: ....

P/s:

  • 2 × 3/12 = 3 × 2/12 = 6 × 1/12 (= 1/2)
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ok done. Thank to me :>

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