9514 1404 393
Answer:
4/5 acre
Step-by-step explanation:
We assume your allocations are ...
goats: 3/5 acre
pigs: 1/5 acre
llamas: 2/5 acre
2 acres is 10/5 acres, so the remaining area is ...
10/5 -3/5 -1/5 -2/5 = (10 -3 -1 -2)/5 = 4/5
4/5 acre is allocated to horses.
Answer:
The shorter side piece of fabric = x = 8 feet
The longer side piece of fabrics = (x + 2) = 10 feet
Step-by-step explanation:
Total yards of fabrics = 6 yards
you need to cut it in two pieces where one is two feet longer than the other.
First piece= x feet
Second piece= x+2 feet
Convert 6 yards to feet
6 yards = 18 feet
First piece + second piece = total piece of fabrics
x + (x+2) = 18
x + x + 2 = 18
2x + 2 = 18
2x = 18 - 2
2x = 16
Divide both sides by 2
x = 16 / 2
x = 8 feet
8 feet = 2.66667 yards
x + 2
= 8 + 2
= 10 feet
10 feet = 3.33333 yards
The shorter side piece of fabric = x = 8 feet
The longer side piece of fabrics = (x + 2) = 10 feet
Answer:
There would be $2,120
Step-by-step explanation:
First figure out what 3% of 2000 is which is 60. Multiply the 60 by 2 to get 120 then add 120 to 2000
Answer:
51/4
Step-by-step explanation:
To begin with you have to understand what is the distribution of the random variable. If X represents the point where the bus breaks down. That is correct.
X~ Uniform(0,100)
Then the probability mass function is given as follows.
Now, imagine that the D represents the distance from the break down point to the nearest station. Think about this, the first service station is 20 meters away from city A, and the second station is located 70 meters away from city A then the mid point between 20 and 70 is (70+20)/2 = 45 then we can represent D as follows
Now, as we said before X represents the random variable where the bus breaks down, then we form a new random variable 
, 
is a random variable as well, remember that there is a theorem that says that
![E[Y] = E[D(X)] = \int\limits_{-\infty}^{\infty} D(x) f(x) \,\, dx](https://tex.z-dn.net/?f=E%5BY%5D%20%3D%20E%5BD%28X%29%5D%20%3D%20%5Cint%5Climits_%7B-%5Cinfty%7D%5E%7B%5Cinfty%7D%20D%28x%29%20f%28x%29%20%5C%2C%5C%2C%20dx)
Where 
is the probability mass function of X. Using the information of our problem
![E[Y] = \int\limits_{-\infty}^{\infty} D(x)f(x) dx \\= \frac{1}{100} \bigg[ \int\limits_{0}^{20} x dx +\int\limits_{20}^{45} (x-20) dx +\int\limits_{45}^{70} (70-x) dx +\int\limits_{70}^{100} (x-70) dx \bigg]\\= \frac{51}{4} = 12.75](https://tex.z-dn.net/?f=E%5BY%5D%20%3D%20%5Cint%5Climits_%7B-%5Cinfty%7D%5E%7B%5Cinfty%7D%20%20D%28x%29f%28x%29%20dx%20%5C%5C%3D%20%5Cfrac%7B1%7D%7B100%7D%20%5Cbigg%5B%20%5Cint%5Climits_%7B0%7D%5E%7B20%7D%20x%20dx%20%2B%5Cint%5Climits_%7B20%7D%5E%7B45%7D%20%28x-20%29%20dx%20%2B%5Cint%5Climits_%7B45%7D%5E%7B70%7D%20%2870-x%29%20dx%20%2B%5Cint%5Climits_%7B70%7D%5E%7B100%7D%20%28x-70%29%20dx%20%20%5Cbigg%5D%5C%5C%3D%20%5Cfrac%7B51%7D%7B4%7D%20%3D%2012.75)
1. 4 • (–3) • 5
so 4 x (-3) = -12 and then -12 x 5 = -60
2. (2.25 x 23) x 4
so (2.25 x 23) 51.75 and then 51.75 x4 = 207
4. 5 x 12 x (-2)
so 5 x 12 = 60 and then 60 x (-2) = -120
5. 35(26)(0) =
so 35 x 26 = 910 and then 910 x 0 = 0
