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Paraphin [41]
3 years ago
13

Sue has 100 dimes and quarters. If the total value of the coins is $21.40, how many of each kind of coins does she have?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

There would be 24 dimes and 76 quarters.

Step-by-step explanation:

In order to find this, start by defining the number of dimes by x and the number of quarters as y. Now we can create a system of equations. Make the first about the total number of coins.

x + y = 100

Make the second about the amount of money.

.10x + .25y = 21.40

Now we can solve using elimination by multiplying the second equation by -4 and adding through.

x + y = 100

-.40x - y = -85.60

-----------------------

.60x = 14.4

x = 24

Now we can use the amount of dimes we have to find the number of quarters.

x + y = 100

24 + y = 100

y = 76

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There are a total of 100 balloons. If the ratio of yellow balloons to blue balloons is 8 to 12, how many of them are yellow
Ivanshal [37]
If you have 8 yellow balloons for every 12 blue balloons, then if you have 20 balloons in total, 8 out of 20 of those balloons will be yellow. Then you can set up this ratio:

\frac{8yellow}{20total} = \frac{Xyellow}{100total}

Then, you can use either cross multiplication or multiply the numerator and denominator by the same number to help solve for x. Personally, I prefer cross multiplication, so that's what I'll show you here:

\frac{8yellow}{20total} = \frac{Xyellow}{100total} \\ 8yellow*100total=20total*Xyellow

Finally, solve for x:

8yellow*100total=20total*Xyellow \\ 8*100=20*x \\ 800=20x \\ 800/20=20x/20 \\ x=40yellow

If you had 100 balloons, you will have 40 yellow balloons.

Hope this helps!!
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3 years ago
Use Vieta's Theorem to solve the problems.
VladimirAG [237]

Answer:

The answer is -2, -17

Step-by-step explanation:

You write a system of equations

x_{1} +x_{2}=-19\\x_{1}-x_{2}=15

Then you solve:

-2, -17

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3 years ago
Toby is making a picture graph. each picture of a books is equal to 2 books he has read. the town for month 1 has 3 pictures of
vovikov84 [41]
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Norma-Jean [14]

Answer:

After the sales tax

$235

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Step-by-step explanation:

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3 years ago
Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2).

Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

Then,

\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}. (I)

Now, recall the definition of the complex exponential:

e^{z}=e^{x+iy} = e^x(\cos y +i\sin y).

So,

e^{2i-3} = e^{-3}(\cos 2+i\sin 2)

e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)

Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

Now, substituting this equality in (I) we get

\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2.

Thus,

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

5 0
3 years ago
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