Answer:
Therefore to prove that ABCD is a parallelogram we need,
BK = DK
CK = AK
Step-by-step explanation:
Given:
The diagonals of quadrilateral ABCD , intersect at point K.
To Find:
Which statement needed to prove that ABCD is a parallelogram?
Solution:
For a Quadrilateral to be a Parallelogram,
- Diagonals Bisect each other.
- Opposite Sides are Parallel and Equal.
- Opposite angles are equal.
Here Diagonals intersect at K
∴ BK = DK ......K bisect Diagonal BD
∴ CK = AK ......K bisect Diagonal AC
Therefore to prove that ABCD is a parallelogram we need,
BK = DK
CK = AK
Answer:
1/6 and diagram is In PDF
Step-by-step explanation:
Let's Do An Example. You Have One Apple And You're Dividing it between you and two of your friends, so each friend gets one third which is 1/3. Then we grab 1/3 of an apple and split in between two more friends so we get 1/6.
8000
is the answer to your question
your welcome!
3/4=0.75
Since 3/4 (of the bar) + 1/4 (of the bar) equals a whole bar (1), and 3/4 (of the bar) + 0.75 equals the whole weight of the bar, 0.75 is 1/4 of the bar. 1/4 times 4 equals 1, and 0.75 times 4 equals 3, so the bar of soap weighs 3 pounds.
Factor the following:
2 x^3 + x^2 - 18 x - 9
Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):
x^2 (2 x + 1) - 9 (2 x + 1)
Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):
(2 x + 1) (x^2 - 9)
x^2 - 9 = x^2 - 3^2:
(2 x + 1) (x^2 - 3^2)
Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):
Answer: (x - 3) (x + 3) (2 x + 1) thus the Answer is C.