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EastWind [94]
3 years ago
10

Another physical property that you can use to separate mixtures is ___________.

Chemistry
1 answer:
fiasKO [112]3 years ago
4 0
Techniques useful for the separation of mixtures include the following: DISTILLATION is the purification of a liquid by heating it to its boiling point, causing vaporization, and then condensing the vapors into the liquid state and collecting the liquid. Separation of two or more liquids requires that they have different boiling temperatures. All boiling temperatures can be reduced by decreasing the pressure on the liquid. EXTRACTION is the removal of one substance from a mixture because of its greater solubility in a given solvent. FILTRATION is the process of removing or "straining" a solid (the chemical term is precipitate) from a liquid by the use of filter paper or other porous material. DECANTING is the pouring of a liquid from a solid-liquid mixture, leaving the solid behind. CENTRIFUGING is the process of separating a suspended solid from a liquid by whirling the mixture at high speed. SUBLIMATION is the physical property of some substances to pass directly from the solid state to the gaseous state without the appearance of the liquid state. Not all substances possess this characteristic. If one component of a mixture sublimates, this property may be used to separate it from the other components of the mixture. Iodine (I2), naphthalene (C10H8, mothballs), ammonium chloride (NH4Cl) and dry ice (solid CO2) are some substances which sublime. CHROMATOGRAPHY is the process of separating a mixture by the distribution of its components between two phases, one phase being stationary and the other phase moving. Some examples of chromatography are gas chromatography, paper chromatography, and thin-layer chromatography.
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Suppose that 98.0g of a non electrolyte is dissolved in 1.00kg of water. The freezing point of this solution is found to be -0.4
Sholpan [36]

Answer:

\large \boxed{\text{392 u}}

Explanation:

1. Calculate the molal concentration

The formula for the freezing point depression by a nonelectrolyte is

\Delta T_{f} = -K_{f}b\\b = -\dfrac{\Delta T_{f}}{ K_{f}} = -\dfrac{-0.465 \, ^{\circ}\text{C}}{\text{1.86 $\, ^{\circ}$C$\cdot$kg$\cdot$mol}^{-1}} = \text{0.250 mol/kg}

2. Calculate the moles of solute

\begin{array}{rcl}b & = & \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\\text{moles of solute} & = & b \times {\text{kilograms of solvent}}\\n & = &\text{0.250 mol/kg} \times \text{1.00 kg}\\ & = & \text{0.250 mol}\\\end{array}

3. Calculate the molecular mass

\begin{array}{rcl}\text{Moles} & = &\dfrac{\text{mass}}{\text{molar mass}}\\\\\text{0.250 mol} & = & \dfrac{\text{98.0 g}}{MM}\\\\MM & = & \dfrac{\text{98.0 g }}{\text{0.250 mol}}\\\\& = &\textbf{392 g/mol}\\\end{array}\\\text{The molecular mass of the solute is $\large \boxed{\textbf{392 u}}$}

3 0
4 years ago
For a particular isomer of C 8 H 18 , the combustion reaction produces 5113.3 kJ of heat per mole of C 8 H 18 ( g ) consumed, un
ale4655 [162]

Answer:

ΔH°f(C₈H₁₈(g)) = -210.9 kJ/mol

Explanation:

Let's consider the combustion of C₈H₁₈.

C₈H₁₈(g) + 25/2 O₂(g) ⟶ 8 CO₂(g) + 9 H₂O(g) ΔH°rxn = − 5113.3 kJ

We can calculate the standard enthalpy of formation of C₈H₁₈(g) using the following expression.

ΔH°rxn = 8 mol × ΔH°f(CO₂(g)) + 9 mol × ΔH°f(H₂O(g)) - 1 mol × ΔH°f(C₈H₁₈(g)) - 25/2 mol × ΔH°f(O₂(g))

1 mol × ΔH°f(C₈H₁₈(g)) = 8 mol × ΔH°f(CO₂(g)) + 9 mol × ΔH°f(H₂O(g)) - 25/2 mol × ΔH°f(O₂(g)) - ΔH°rxn

1 mol × ΔH°f(C₈H₁₈(g)) = 8 mol × (-393.5 kJ/mol) + 9 mol × (-241.8 kJ/mol) - 25/2 mol × 0 kJ/mol - (− 5113.3 kJ)

ΔH°f(C₈H₁₈(g)) = -210.9 kJ/mol

5 0
3 years ago
A sample of a compound is found to consist of 0.44g H and 6.92g O what’s its formula
Lynna [10]

Answer:

Explanation:

H = 0.44/1.01 = 0.4356

O = 6.92/16 = 0.4319

This gives a 1:1 ratio. So the closest thing you could say is the formula is 0H

Going to your chemical storage room, you could justify that it is H2O2 or hydrogen peroxide. The question needs one more fact to make the answer certainty.

3 0
3 years ago
Which structure regulates water loss and gas exchange
Xelga [282]
If you're referring to plants, your answer is the Epidermis.

Hope this helps! :)


8 0
3 years ago
Need helpppppppppppppppppppppppppp with 3
ira [324]

Answer:

13. 8 hrs

12. 8.89 meters per second squared

11. -0.75 meters per second squared

7 0
2 years ago
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