Answer:
A
Explanation:
an element contains only one kind of particle
A) LiAlH4
b) Ph(3)SnH
c)Na in dry ether(Wurtz reaction)
An old penny rusting, remember you can’t undo a chemical change
Explanation:
Given that,
The frequency of electromagnetic spectrum is 
(A) Let the wavelength of this radiation is
. We know that,

So, the wavelength of this radiation is
.
(B) Let E is the energy associated with this radiation. Energy of an electromagnetic radiation is given by :

h is Planck's constant

1 kcal = 4184 J
It means,

Hence, this is the required solution.
Element. Everything is else is a mixture, therefore not pure.