Answer:
7.98 g of glucose are needed to prepare 399 mL of glucose solution
Explanation:
2.0 % m/v
This data represents, a sort of concentration for solutions.
It means that, our solution contains 2 g of solute, in this case glucose, which are contained by 100 mL of solution.
We only have to make a rule of three, in order to solve the question:
In 100 mL of glucose solution, we have 2 g of solute
In 399 mL of glucose solution, we may have:
(399 . 2) / 100 = 7.98 g
