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Pani-rosa [81]
2 years ago
8

Hey can someone please help me with this question thanks!

Mathematics
1 answer:
-BARSIC- [3]2 years ago
6 0
The dependent variable is the number of votes
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What is the inverse of the function??
Firlakuza [10]
\(\begin{matrix}
y=ln(x+3)\\
e^y=x+3\\
e^y-3=x\\
swap ~x~and~y\\
 \huge\underline{y=e^x-3}}
 \end{matrix}\)


To get the inverse of any function f(x) [ just make sure that it passes the horizontal line test] follow the steps:

- Solve for x, i.e separate x in one side and the other terms in the other side, included f(x).

- Swap x and f(x).

- The result is the inverse of the original function f^{-1}(x).

-------------------------

Apply that on your function
\(\begin{matrix}
y=ln(x+3)\\
e^y=x+3\\
e^y-3=x\\
swap ~x~and~y\\
 \huge\underline{y=e^x-3}}
 \end{matrix}\)




5 0
2 years ago
a hotel has enough food for 125 guest to last 16 days. how long will the food last if 25 more guest check-in to the hotel ?
timama [110]
3.2 less days than 16 because each 25 is 5 than 16 divide by 5 is 3.2
6 0
2 years ago
How would eight billion, nine hundred seventy-seven thousand, thirteen be written in standard form?
zheka24 [161]

Answer:

8 billion > 8,000,000,000

977 thousand > 977,000

13> 13

8,000,977,013

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Figure ABCD is a parallelogram.
STatiana [176]
The answer is 14 units
7 0
2 years ago
Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i
aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175

Positive when there is raritanium:

98% of 13%

P(A) = 0.98*0.13 = 0.1274

What is the probability the rock sample actually contains raritanium?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967

0.967 = 96.7% probability the rock sample actually contains raritanium

7 0
2 years ago
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