Answer:
82.79MPa
Step-by-step explanation:
Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa
Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,
Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)
The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))
But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ
σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)
p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.
Hope this helps!!
Answer:
1 = 140 2 = 70
Step-by-step explanation
1 is 140 because it is the same as 140 and 2 is 70 because it is the same angle as 70.
Answer:
The answer is 12 and 4
Step-by-step explanation:
Answer:
y = 2/5x
Step-by-step explanation:
Perpendicular lines are lines which have negative reciprocal slopes of each other.
The line y = -5/2 x + 2 has slope -5/2. Therefore its perpendicular slope will be 2/5.
The equation can cross anywhere on the y-axis for its y-intercept since no specific point is given. Here I chose (0,0).
y = 2/5x
Answer:
The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.
Step-by-step explanation:
By definition of rectangular prism, we get the respective formulas for the volumes of the community swimming pool and the wadling pool, respectively:
Community swimming pool
Wading pool
Where:
l – Length of the swimming pool, measured in feet.
h – Depth of the swimming pool, measured in feet.
w – Width of the swimming pool, measured in feet.
– Volume of the community swimming pool, measured in cubic feet.
– Volume of the wading swimming pool, measured in cubic feet.
The ratio of the volume of the community swimming pool to the volume of the wadling pool is:
The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.
