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Triss [41]
3 years ago
9

Graph and solve the system. 3=4y+x 4y=-x+3

Mathematics
2 answers:
slava [35]3 years ago
4 0

How to solve it is shown with the process of Substitution in the following pictures. (The steps are listed in order from the first picture to the second picture.)

Hope this helps!

NeTakaya3 years ago
3 0

d) infinitely many solutions

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Janeen wants to use the distributive property to find the value of 14⋅26+14⋅53. Which expression can she use?
murzikaleks [220]

Answer:

14(26+53)

Step-by-step explanation:

14*26 + 14*53 can be rewritten as 14(26+53).  The value of this expression is 14(79) = 1106.


5 0
3 years ago
Read 2 more answers
Can someone pleasee help
katrin2010 [14]

Answer:

y-intercept: (0, 5)

Step-by-step explanation:

This parabola has an equation of -x² + 4x + 5.

It's y-intercept is (0, 5).

It's x-intercepts or roots are (-1, 0) and (5, 0).

It's vertex is (2, 9).

___________________________________

Keep in mind that the y-intercept is when x = 0.

6 0
3 years ago
Without solving it, determine the nature of the roots of this equation:
ycow [4]
<h2>Answer:</h2>

x = 1, -4

Step-by-step explanation:

Find the roots of  x:

2  +  3

x  −  4  =  0  by solving for  x

.

6 0
3 years ago
Describe the vertical line test.
SpyIntel [72]

Answer:

The vertical line test is used to determine whether a graph line is a FUNCTION

when there is a line on a graph and you want to know if it is a function. put a straight line through it, up and down, and if it only passes through ONE POINT then it is a function if it touches the graph more than once than it is not.i

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Marlene is solving a number puzzle involving three rational numbers a, b, and c. Here are her clues:
rusak2 [61]
A/c = 8.....a = 8c
a * c = 2 ...a = 2/c
a/b = -16 ...a = -16b
a * b = -1....
b/c = -0.5

2/c = 8c
2 = 8c^2
1/4 = c^2
sqrt 1/4 = c
0.5 (or 1/2) = c <===

a * c = 2
0.5a = 2
a = 2/0.5
a = 4 <===

a = -16b
4 = -16b
4/-16 = b
-1/4 (or - 0.25) = b <===
5 0
3 years ago
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