Answer:

Step-by-step explanation:
<u>Solving Equations Using Successive Approximations</u>
We need to find the solution to the equation

where


The approximation has been already started and reached a state for x=2.5 where


The difference between the results is 0.25, we need further steps to reach a good solution (to the nearest tenth)
Let's test for x=2.4


The new difference is -0.2+0.24=0.04
It's accurate enough, thus the solution is

Two eventis are independent if knowledge about the first doesn't change your expectation about the second.
a) Independent: After you know that the first die showed 4, you stille expect all 6 numbers from the second. So, the fact that the first die showed 4 doesn't change your expectation about the second die: it can still show numbers from 1 to 6 with probability 1/6 each.
b) Independent: It's just the same as before. After you know that the first coin landed on heads, you still expect the second coin to land on heads or tails with probability 1/2 each. Knowledge about the first coin changed nothing about your expectation about the second coin.
a) Dependent: In this case, there is a cause-effect relation, so the events are dependent: knowing that a person is short-sighted makes you almost sure that he/she will wear glasses. So, knowledge about being short sighted changed your expectation about wearing glasses.
The inequality would be 50w + 100 >_ 18,000 ( the _ goes under the > but I cannot do that on my phone )
Answer:
12 two times or 4 eight times