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jeka57 [31]
3 years ago
14

 How many​ flowers, spaced every 3 ​in., are needed to surround a circular garden with a 150​-ft ​radius? Use 3.14 for pi.

Mathematics
1 answer:
BARSIC [14]3 years ago
5 0

Answer:

3,768\ flowers

Step-by-step explanation:

step 1

Find the circumference of the circular garden

The circumference of the circle is equal to

C=2\pi r

we have

r=150\ ft

\pi=3.14

substitute the values

C=2(3.14)(150)=942\ ft

step 2

<em>Convert feet to inches</em>

Remember that

1\ ft=12\ in

942\ ft=942*12=11,304\ in

step 3

Divide the circumference by 3 in to calculate the number of flowers

11,304/3=3,768\ flowers

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3 years ago
Cuanto es (2x+2y=20) (-2x-6y=-52) con método de igualación y método de suma y resta
Nataly_w [17]

x =2       y =8

2x + 2y=20

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6 0
3 years ago
A package states that there are 60 calories in 12 crackers and 75 calories in 15 crackers. Since the relationship is proportiona
AveGali [126]

Answer:

900 calories

Step-by-step explanation:

First you have to find the unit rate, how many calories are there in ONE cracker? To find that you have to divide 60 ÷ 12 = 5 and to check with the other one, 75 ÷ 15 = 5

So, one cracker is 5 calories. Now, how many calories are in 180 crackers? You multiply, 180 x 5 = 900

That means there are 900 calories in 180 crackers.

Hope that helps and have a great day!

5 0
3 years ago
Hey guys can u tell me if the top is correct if its not can u show me step by step what to do and what the answer will be and ca
ASHA 777 [7]
You have the right idea and you are close to the correct answer. However that's not what your teacher is looking for in terms of steps.

The starting inequality is b + 8 \ge 20
She starts off selling 8 buckets. Then she sells b more to get a total of b+8
This total must be 20 or larger which is why I set b+8 greater than or equal to 20

Solve for b by subtracting 8 from both sides

b + 8 \ge 20

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So she needs to sell at least 12 more buckets to reach her goal

If you graphed this on a number line, then you would draw a closed circle at 12. Then shade to the right of the close circle. 
6 0
3 years ago
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