ANSWER QUICKLY PLEASE ITS URGENT

Mathematics

1 answer:

sladkih [1.3K]3 years ago

3 0

Answer:

The answer to this is -5

Step-by-step explanation:

To do this, just do -125 to the 1/3 power. This is because you need to do the reverse of the order of operations.

You might be interested in

Please help me fast its for plato

Alenkinab [10]

Answer:

5/b

Step-by-step explanation:

you would want to add your 1+4 together on top of your b which is your common denominator in this case and you should end up with 5/b

7 0

3 years ago

Please don’t troll include work

zheka24 [161]

4 1/8-2 3/4= 4 1/8 - 2 6/8= 1 3/8

2 3/5 + 1 5/6 = 2 18/30 + 1 25/30= 3 43/30 = 4 13/30

8 9/12 + 2 3/8= 8 18/24 + 2 9/24= 10 27/24 = 11 3/24= 11 1/8

3 1/3 - 1 1/2= 3 2/6 - 1 3/6 = 2 8/6 - 1 3/6= 1 5/6

4 0

3 years ago

Which set of ordered pairs represents a function? (1 point) {(0, 1), (1, 3), (1, 5), (2, 8)} {(0, 0), (1, 2), (2, 6), (2, 8)} {(

Aleonysh [2.5K]

Answer:

{(0, 2), (1, 4), (2, 6), (3, 6)}

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the value of z in the table?

Genrish500 [490]

The value is 30.9 liters

6 0

2 years ago

Find a formula for the described function. A rectangle has perimeter 16 m. Express the area A of the rectangle as a function of

Alex17521 [72]

Part A:

Let the length of one of the sides of the rectangle be L, then the length of the other side is obtained as follow.

Let the length of the other side be x, then

$2(L+x)=16 \\ \\ \Rightarrow L+x=8 \\ \\ \Rightarrow x=8-L$

Thus, if the length of one of the side is x, the length of the other side is 8 - L.

Hence, the area of the rectangle in terms of L is given by

$L(8 - L) = 8L-L^2$

Part B:

To find the domain of A

Recall that the domain of a function is the set of values which can be assumed by the independent variable. In this case, the domain is the set of values that L can take.

Notice that the length of a side of a rectangle cannot be negative or 0, thus L cannot be 8 as 8 - 8 = 0 or any number greater than 8.

Hence the domain of the area are the set of values between 0 and 8 not inclusive.

Therefore,

$dom(Area)=0\ \textless \ L\ \textless \ 8 \ or \ (0, 8)$

3 0

3 years ago