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3 years ago

The volume of a barn is given by the formula V = = r2h.

Mathematics

1 answer:

HACTEHA [7]3 years ago

4 0

Answer:

it is what it is take a guess

Step-by-step explanation:

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Given f(x)=x+7 and g(x)=x-3 what is f(x)+g(x) ? A.2x+4 B.10x C.2x-7 D.-2x+10

Zinaida [17]

F(x)+g(x) = (x+7) + (x-3) =
x + 7 + x - 3 =
2x + 4

<span>
A.2x+4</span>

7 0

3 years ago

Read 2 more answers

Log In a survey of a town, 63% of residents own a car, 20% of residents own a truck, and 4% of residents own both a car and a tr

yan [13]

Answer:

Step-by-step explanation:

Let T= truck

C= Car

We are looking for the probability that someone owns a truck given that they own a car

P(T|C)

The conditional probability formula is as follows:

P(T|C)=(T∩C)/C

plugging in numbers..

.04/.63=6.3492% which rounds to 6%

4 0

3 years ago

Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po

Troyanec [42]

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, $\sigma=0.2$ ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

$P(x\geq 10)=0.99$

Assume the bag weight distribution is bell-shaped

Therefore,

$P(\frac{x-\mu}{\sigma}\geq 10)=0.99$

We know that

$z=\frac{x-\mu}{\sigma}$

Using the value of z

Now,

$\frac{10-\mu}{0.2}=0.99$

$10-\mu=0.99\times 0.2$

$\mu=10-0.99\times 0.2$

$\mu=9.802$

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

5 0

3 years ago

If one gallon of paint covers 350 square feet how many gallons will you need to cover a wall that is 138 inches by 102 inches

frosja888 [35]

138in x 102in = 14076in sq.
14076/350=40.217
41 gallons of paint.

6 0

3 years ago

Gabriele's Pie Shop sold 80 pies last month: 7/10 were apple pies and 1/10 were peach pies. How many pies were neither apple nor

AleksAgata [21]

Answer:

16 pies were neither apple nor peach.

Step-by-step explanation:

8/10, or 4/5 of the 80 apple pies were either apple or peach, which 4/5 of 80 is 64. The remaining pies will be neither apple nor peach. 80 - 64 = 16.

7 0

3 years ago