Question

Find the period of the function. y=3 sin x/8

Answer 1

Answer:

The period of given function is  $Period = 16\pi$

So, Option B is correct.

Step-by-step explanation:

In this question we need to find the period of the function y= 3 sin x/8

The formula used to find period of function is: $\frac{2\pi }{b}$

We need to know the value of b.

To find the value of b we compare the standard equation with the equation of function given.

Standard Equation: y = a sin(bx - c) +d

Given Equation: y= 3 sin(x/8)

Comparing we get:

a= 3

b= 1/8

c= 0

d=0

So, we get the value of b i.e 1/8. Putting it in the formula to find period of given function.

$Period = \frac{2\pi }{b}$

$Period = \frac{2\pi }{\frac{1}{8}}$

Solving,

$Period = 2\pi *8$

$Period = 16\pi$

So, the period of given function is  $Period = 16\pi$