Use the information given to answer the question.

Mathematics

1 answer:

Usimov [2.4K]2 years ago

4 0

Comparing the functions, it is found that:

The function Kimora's travel based on Jim's travel is of: D. g(x) = f(x) + 80.
Lonnie's function based on Kimora is: B. h(x) = g(x - 2).

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Jim's equation is of:

$f(x) = 140 - 55x$

Kimora's equation is of:

$g(x) = 220 - 55x$

The -55x term is common to both functions, while the constant on g is 80 more than f, thus:

$g(x) = f(x) + 80$

Which means that the answer to the first question is given by option D.

Lonnie started traveling two hours before Kimora's, using the same equation of motion, just with the input x reduced by 2, thus:

$h(x) = g(x - 2)$

Which means that the answer to the second question is given by option B.

A similar problem is given at brainly.com/question/24759429

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Find the common fraction equivalent to 0.12

jonny [76]

The answer is: " $\frac{4}{33}$ "  .
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Given: 0.1212121212..... repeating ; write that value as a fraction;
______________________________________________________
In other words; we are given: "0.1212121212..... repeating infinitely" ;

→ that is to say; "0.12 ... ; {the "12" decimal portion repeats infinitely} ;
_______________________________________________________
→ We write this value, as a fraction, as: "12/99" ;
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→Explanation:
__________________________________________

Note: "0.99999999...... repeating infinitely; = "1" .
_________________________________________
→Since:

Let us say that we have:

"x = 0.999999 ; repeating infinitely;

In order words, let us say we have: "x = 0.9.... ; the "9" decimal repeats infinitely;
_____________________________________________________
Then "10x" ; (that is: "10" multlipled by "x"; or "10*x" or "10x" ); is equal to:

"10" * (0.999999.....) = 9.99999999...... (the "9" decimal repeats infinitely);

in other words: 10x = 9.99999999....

Divide each side by "10" ;

to get "x = 0.9999999....." ; the decimal "9" repeats indefinitely...." ;

But if you have: "10x = 10" ; divide each side of the equation by "10" ;
you get: "x = 1" .
____________________
Also, if "x = 0.9999...(repeating infinitely);

then: 10x = 9.99999.
_______________________________________________
10x = 9.999999999999999......
−   x = 0.999999999999999.......
_____________________________________
9x = 9.00000000000000000000.....

→ 9x = 9 ;

Divide each side of the equation; to get;

9x /9 = 9/ 9 ; to get: x = 1 ; and we have: x = 0.9999.... ; so
x= 0.99999.... = 1 ;
__________________________________________________
So, if the numbers "12" is repeating, we divie "12" by "99" ;
that is; we divide "12" by "two 9's" ; since "12" is a "TWO-digit number"; a "two-digit number" is being repeated infinitely.
________________________________________
So; 0.12121212.....(the "12" is the decimal that repeats infinitely);

= 12/99 ; which can be simplified;

Divide each side (both the numerator AND the denominator); by "3" ;
_________________________________________
" 12/99 " = "(12÷3) / (99÷3) = 4/33 " .
_________________________________________
The answer is: $\frac{4}{33}$   .
_________________________________________

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