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3 years ago

Sin75 in sure form using trigonometric identity

Mathematics

2 answers:

Lyrx [107]3 years ago

6 0

Answer:

sin75°=sin(45°+30°)=(√6+√2)/4

Step-by-step explanation:

sin75°=sin(45°+30°)

=sin45°*cos30°+cos45°*sin30°

=(√2/2)* (√3/2)+ (√2/2)*(1/2)

=(√6+√2)/4

<h2>Brainliest? Please! </h2>

baherus [9]3 years ago

5 0

Answer:

Step-by-step explanation:

<em>sin75°=sin(45°+30°)</em>

=sin45°*cos30°+cos45°*sin30°

=(√2/2)* (√3/2)+ (√2/2)*(1/2)

=(√6+√2)/4

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First, let's factor both of these numbers.

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2 years ago

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Answer:

$-3x^3(-2x^2+4x-3)$ simplifies to $6x^5-12x^4+9x^3$

Step-by-step explanation:

Given expression $-3x^3(-2x^2+4x-3)$

We have to simplify the above expression,

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Multiply each term in brackets by $-3x^3$ , we get,

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Solving further, using $x^n\cdot x^m=x^{n+m}$ we get,

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Answer:

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