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3 years ago

What is the monomial if a square of a monomial is: 0.0001 * a^8 * x^4

Mathematics

1 answer:

pav-90 [236]3 years ago

7 0

Answer:

$0.01a^{4} x^{2}$ or $- 0.01a^{4} x^{2}$

Step-by-step explanation:

Let the monomial is M and M² is given by $0.0001 a^{8} x^{4}$ .

Now, we have to find M.

We can rearrange the expression of M² as a square of the monomial.

Hence, $M^{2} = [0.01a^{4}x^{2}]^{2}$

⇒ $M = 0.01a^{4} x^{2}$ or $M = - 0.01a^{4} x^{2}$ .

Therefore, the required monomial is $0.01a^{4} x^{2}$ or $- 0.01a^{4} x^{2}$

( Answer )

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A certain test preparation course is designed to help students improve their scores on the USMLE exam. A mock exam is given at t

bogdanovich [222]

Answer:

The critical value is $T = 4.604$ .

The 99% confidence interval for the average net change in a student's score after completing the course is (6.236, 22.164).

Step-by-step explanation:

The first step to solve this question is finding the sample mean and sample standard deviation:

14,11,18,9,19

Sample mean is sum of all values divided by the number of values. Thus:

$\overline{x} = \frac{14+11+18+9+19}{5} = 14.2$

The sample standard deviation is the square root of the division of the sum of the subtractions squared of each value and the mean, and the number of values. Thus:

$s = \sqrt{\frac{(14-14.2)^2+(11-14.2)^2+(18-14.2)^2+(9-14.2)^2+(19-14.2)^2}{5}} = 3.868$

Confidence interval:

We have the standard deviation for the sample, and so we use the t-distribution to build the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 5 - 1 = 4

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 4 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 4.604.

The critical value is $T = 4.604$ .

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 4.604\frac{3.868}{\sqrt{5}} = 7.964$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 14.2 - 7.964 = 6.236.

The upper end of the interval is the sample mean added to M. So it is 14.2 + 7.964 = 22.164.

The 99% confidence interval for the average net change in a student's score after completing the course is (6.236, 22.164).

8 0

3 years ago

1+1<br> try to guess :) you will get 33 points

WARRIOR [948]

Answer:

11............... ...?

5 0

4 years ago

Read 2 more answers

The Roberts family uses a container shaped like a cylinder to recycle aluminum cans. It has a height of 4 feet and a diameter of

Vedmedyk [2.9K]

The volume of the container is the amount of can in it

The contents weigh 1047.1 ounces

<h3>How to determine the weight of the container?</h3>

The given parameters are:

Volume = 28.3 cubic feet

Average weight of can = 37 ounces per cubic foot

So, the weight of the container would be:

Weight = Volume * Average weight of can

Substitute known values

Weight = 28.3 cubic feet * 37 ounces per cubic foot

Evaluate the product

Weight = 1047.1 ounces

Hence, the contents weigh 1047.1 ounces

Read more about volumes at:

brainly.com/question/1972490

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2 years ago

In its January 25, 2012, issue, the Journal of the American Medical Association (JAMA) reported on the effects of overconsumptio

Leviafan [203]

Answer:

b. experiment

Step-by-step explanation:

An observational study is one in which the researchers monitor the effect of a risk factor on subjects without introducing interventions for the purpose of noting differences in results. An experiment is mainly a randomized control trial where subjects are assigned to groups and chosen by chance. Interventions are also introduced by the researchers so as to note the different possible results within the groups and among participants.

The above-described process incorporates an experiment and that is why the researchers introduce protein level diet as interventions. It also employs the random assignment of subjects to different groups so as to improve the accuracy of the process.

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3 years ago

I need help on this one

olga nikolaevna [1]

Answer:

1. Co - payment

2. Coinsurance

3. Deductible

Step-by-step explanation:

1. Deductible:

A certain amount that you pay before the insurance company pays a claim.

2. Coinsurance:

The percentage of the cost that you share with the insurance company

3. Co-payment:

A fixed amount that you pay the provider at the time of service. {Usually, a standard procedure in Health Insurance.]

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3 years ago