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3 years ago

A trinomial with a leading coefficient of 3 and a constant term of -5

Mathematics

2 answers:

Lady_Fox [76]3 years ago

6 0

Answer:

A trinomial with a leading coefficient of 3 and a constant term of -5 is $3x^2+x-5$ .

Step-by-step explanation:

To find : A trinomial with a leading coefficient of 3 and a constant term of -5 ?

Solution :

A trinomial is a polynomial with three terms is in the form of $ax^2+bx+c$ .

where, a is the leading coefficient, b is the middle coefficient of x and c is the constant.

A trinomial with a leading coefficient of 3 and a constant term of -5.

Here, a=3,c=-5 and consider b=1,

So, $3x^2+x-5$

Therefore, a trinomial with a leading coefficient of 3 and a constant term of -5 is $3x^2+x-5$ .

Yakvenalex [24]3 years ago

4 0

This is one example of a trinomial with a leading coefficient of 3 and a constant term of -5

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Step-by-step explanation:

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Step2247 [10]

Answer:

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Step-by-step explanation:

Given the points

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$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

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Refine

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Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

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Answer:

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