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Dvinal [7]
4 years ago
10

Which shows 2/3 and 3/4 written as a pair of fractions with a common denominator ? 2/3 and 4/3 or 6/9 and 6/8 or 2/12 and 3/12 o

r 8/12 and 9/12
Mathematics
2 answers:
cluponka [151]4 years ago
7 0
8/12 and 9/12 shows them written both with a common denominator. When you find common denominators, you have to do the same to the numerator and denominator. The other answers have not done this. So we know it will not be the first choice because 3/4 cannot become a greater number by multiplying both the numerator and denominator by the same number. We know it won't be the second option because 3 isn't a factor of 8. It won't be the third option either because 3 is not a multiple of 2. So we are left with the last one.
Setler79 [48]4 years ago
4 0
You have 2/3 and 3/4
You need to find common denominator
You need to multiply both bottoms to get the same number on the bottom
Shorter story you need to multiply the bottom numbers by a number to get the same number on the bottom
When you get that make sure you multiply both tops by the same number
2/3 3/4

3x4= 12. 4x3=12.
Your denominator is 12
Now multiply the numerator by the same number you multiplied the denominator by.
2x4=8. 3x3=9
Answers
8/12 and 9/12
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3 years ago
Simplify 7/341 and give step by step explanation! I will mark you a brainliest.​
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Step-by-step explanation:

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A college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of
Alla [95]

Answer:

80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

Step-by-step explanation:

We are given that a college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of hours they watch per week. The results are provided below;

<u>Hours of TV per week (X)</u>: 6, 14, 13, 6, 16, 10, 19, 4, 5, 5, 18, 8, 7, 14, 8, 8, 9, 12, 6, 5.

Firstly, the Pivotal quantity for 80% confidence interval for the true average is given by;

                                P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of hours of TV watched per week = \frac{\sum X}{n} = 9.65

            s = sample standard deviation = \sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }  = 4.61

            n = sample of people = 20

           \mu = true average number of hours of TV watched per week

<em>Here for constructing 80% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<u>So, 80% confidence interval for the true average, </u>\mu<u> is ;</u>

P(-1.33 < t_1_9 < 1.33) = 0.80  {As the critical value of t at 19 degrees of

                                               freedom are -1.33 & 1.33 with P = 10%}  

P(-1.33 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.33) = 0.80

P( -1.33 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

P( \bar X-1.33 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

<u>80% confidence interval for</u> \mu = [ \bar X-1.33 \times {\frac{s}{\sqrt{n} } } , \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ]

                                         = [ 9.65-1.33 \times {\frac{4.61}{\sqrt{20} } } , 9.65+1.33 \times {\frac{4.61}{\sqrt{20} } } ]

                                         = [8.28 hours, 11.02 hours]

Therefore, 80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

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17 is what percent of 34​
Stels [109]

Answer:

50%

Step-by-step explanation:

17/34 = .50

3 0
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