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stich3 [128]
3 years ago
9

John bought a crate of floor tiles $100. The crate had 5 boxes pf floor tiles. Each box contained 40 floor tiles. Write an

Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer:

i feel like were in the same school because we have the same answers, but check my recent question since people answered mine

Step-by-step explanation:

You might be interested in
Yesterday's afternoon temperature was 21°F. It plunged overnight to -3°F. How many degrees did the temperature drop? A) 3° B) 18
LiRa [457]

Answer: B) 18° C

Step-by-step explanation:

21+(-3) = 21 - 3

            = 18

7 0
3 years ago
Read 2 more answers
Use Pascal’s Triangle to determine the fifth term of the expansion of (x + 3)7
ValentinkaMS [17]

Answer:

2835x^5.

Step-by-step explanation:

By Binomial Theorem, T(r+1) = nCr * a^(r+1) * b^r.

Term 5 = 7C4 * x^5 * 3^4

= 35 * x^5 * 3^4

= 2835x^5.

7 0
3 years ago
Q # 1 Graph the function<br>Y = |X + 2| - 3
Svetllana [295]
First of all we know the Absolute Value Function that is:

\left | x \right |= \left \{ {{x \ \ \ \ x \geq 0} \atop {-x \ \ \ \ x\ \textless \ 0}} \right.

This is called the Parent Function <em>of the Absolute Value Function.</em>

From the equation:

y=\left | x+2 \right |-3

The term:

\left | x+2 \right |

means that the the Parent Function is <em>shifted</em> two units <em>to the left</em>.

On the other hand, the term:

-3

means that the function \left | x+2 \right | is <em>shifted</em> three units <em>downward. </em>So the result is the graph shown below

4 0
3 years ago
Read 2 more answers
Which of the following graphs shows the solution set for the inequality below? 3|x + 1| &lt; 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
2 years ago
In particular, OLS for the multiple regression model involves selecting parameters that will minimize:___________
brilliants [131]

Answer:

Ordinary Least Square (OLS) for the multiple regression model involves selecting parameters of a straight line function that will minimize <u>the sum of the squares of the variance in the given dataset and those forecasted by the straight-line function.</u>

Cheers

8 0
3 years ago
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