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3 years ago

Please help me with this I will mark you as brainliest!

Mathematics

2 answers:

Wittaler [7]3 years ago

5 0

Answer:

0.74

Step-by-step explanation:

Of the 30% of boys, 60% arrive by car, that is

60% of 30% = 0.6 × 0.3 = 0.18

Since 30% of the children at school are boys, then 70% are girls.

Of the 70% of girls, 80% arrive by car, that is

80% of 70% = 0.8 × 0.7 = 0.56

Probability of choosing a child from the school is

P( boy ) or P(girl) = 0.18 + 0.56 = 0.74

iragen [17]3 years ago

4 0

Answer:

.74

Step-by-step explanation:

First, you know that 30% are boys and 70% are girls. Then, take 60% of 30% and 70% of 80%. From there you get .74 as the probability of a randomly chosen child having taken a car to school.

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Answer both and brainliest you will get

nekit [7.7K]

Answer:

1. The first one is 1/4

2. The 2nd one is 2/5

Step-by-step explanation:

This answer is right because I'm like that.

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2 years ago

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Which equation is a function of x?

GrogVix [38]

Answer:

a because a variable cannot be a variable

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Find the volume of the solid of revolution formed by rotating about the x--axis the region bounded by the given curves.

hichkok12 [17]

Answer:

$2\pi(e^2-e^{-4})$

Step-by-step explanation:

We are given: $f(x)=2e^x$

So, the integral will be used to calculate the volume.

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4 years ago

1. If your final exam counts as 20% of your semester grade in a class, and you have an 88% going into the final, what percent mu

zysi [14]

.8 (88%)+.2x=90%
70.4%+.2x=90%

subtract 70.4% from 90% to get 19.6%
make the .2x into 2 and the 19.6 into 196
divide 196 by 2 to come up with the answer of 98%.
you will need a 98% to have a 90% for the final grade

4 0

3 years ago

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Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

6 0

3 years ago