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2 years ago

What would be the surface area of the figure..

Mathematics

1 answer:

valina [46]2 years ago

8 0

Answer:

Step-by-step explanation:

The surface area of the figure is sum of areas of two triangles and three ractangles:

$A=2\cdot\frac12\cdot10\cdot8,3+3\cdot10\cdot14=83+420=503\,cm^2$

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vova2212 [387]

Answer: 100

Hi!

ok so the Pythagorean theorem is

$c=\sqrt{x} a^2+b^2=\sqrt{x} 8^2+6^2=10$

so the other side is 10.

the square 8 is 8*8

and square 6 is 6*6

so the other square is 10*10=100.

so the area of the blank square is 100.

Step-by-step explanation:

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2 years ago

The width of a rectangle is 4 less than half the length. if l represents the length, which equation could be used to find the wi

g100num [7]

W-4=1/2L
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2 years ago

5 x 7824984262984 ÷ 76

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2 years ago

PLEASE HELP! 30 points and will award brainliest!

solmaris [256]

Your answer will be 150

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2 years ago

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

2 years ago