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ivolga24 [154]
3 years ago
12

Pls help I'll give brainliest!

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0

Answer:

95

Step-by-step explanation:

t_n =  {n}^{2}  - 5 \\  \therefore \: t_{10} =  {10}^{2}  - 5 \\ \therefore \: t_{10} = 100  - 5 \\ \huge \red{ \boxed{\therefore \: t_{10} = 95 }}\\

10th term of the sequence is 95.

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1. The length of a rectangle is 3 in. more than the width. The perimeter of the rectangle is 24 in.
Westkost [7]

Answer:

Let the width be x

Length = x + 3

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Hope this helps!

4 0
4 years ago
Jbnhdfjkgdshbajkifvdguigdfbugdfbnjkvgfvfd
MaRussiya [10]

Answer:

I completely understand

Step-by-step explanation:

3 0
3 years ago
If x2+1/x2=18, find the value of x3−1/x3
Elden [556K]

Answer:

There are 2 answers : 76 or -76

Step-by-step explanation:

x^2+\dfrac{1}{x^2} =18\\\\(x-\dfrac{1}{x} )^2=x^2+\dfrac{1}{x^2} -2=18-2=16\\\\x-\dfrac{1}{x}=4\ or\ x-\dfrac{1}{x}-4\\\\(x-\dfrac{1}{x} )^3=x^3-\dfrac{1}{x^3} -3x^2*\dfrac{1}{x}+3x*\dfrac{1}{x^2}\\\\=x^3-\dfrac{1}{x^3}-3(x-\dfrac{1}{x})\\\\x^3-\dfrac{1}{x^3}=(x-\dfrac{1}{x} )^3+3(x-\dfrac{1}{x})\\\\if\ x-\dfrac{1}{x}=4\ then \ x^3-\dfrac{1}{x^3}=4^3+3*4=64-12=76\\\\if\ x-\dfrac{1}{x}=-4\ then \ x^3-\dfrac{1}{x^3}=(-4)^3+3*(-4)=-64-12=-76\\\\

7 0
3 years ago
Read 2 more answers
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