Question

Which of the following is equivalent to the inequality shown below?

Answer 1

Answer:

$4x + 0.9 \geq 0.1$ is equivalent to the inequality $40x+9 \geq 1$

Step-by-step explanation:

Given inequality : $4x + 0.9 \geq 0.1$

We are supposed to find Which of the following is equivalent to the inequality

$4x + 0.9 \geq 0.1$

$\Rightarrow 4x+\frac{9}{10} \geq \frac{1}{10}$

Multiply both sides by 10

$\Rightarrow 4(10)x+\frac{9}{10}(10) \geq \frac{1}{10}(10)$

$\Rightarrow 40x+9 \geq 1$

$4x + 0.9 \geq 0.1$ is equivalent to the inequality $40x+9 \geq 1$

So, Option B is true

B) $40x+9 \geq 1$