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3 years ago

Find the solution to the systems. x+y=1 and 3y=-3x+3

Mathematics

1 answer:

jenyasd209 [6]3 years ago

3 0

Answer:

infinite number of solutions

Step-by-step explanation:

x+y=1

3y=-3x+3 ⇒ y=-x+1 ⇒ y+x=1

both equations are the same, so they have infinite number of solutions

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The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

2 years ago

Read 2 more answers

How many solutions does -46+23=46x+23

Slav-nsk [51]

Answer:

x = -1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−46+23=46x+23

(−46+23)=46x+23(Combine Like Terms)

−23=46x+23

Step 2: Flip the equation.

46x+23=−23

Step 3: Subtract 23 from both sides.

46x+23−23=−23−23

46x=−46

Step 4: Divide both sides by 46.

46x/46 = -46/46

6 0

2 years ago

The large rectangle below represents one whole. What percent is represented by the shaded area? (URGENT)

nikitadnepr [17]

Answer:

40%

Step-by-step explanation:

The whole rectangle is split into 5 parts. Two out of 5 parts are shaded.

Set up a fraction:

$\frac{\text{Shaded}}{\text{Whole}}=\frac{2}{5}$

Convert into a decimal:

$\frac{2}{5}= 0.4$

Multiply the decimal by 100 to get the percent:

$0.4*100=40$

So, forty percent of the rectangle is shaded.

Hope this helps.

4 0

2 years ago

Read 2 more answers

Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.

TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

$(x-2)\\ (x-3)\\ (x-5)$