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topjm [15]
3 years ago
15

Pls help with the question​

Mathematics
1 answer:
eduard3 years ago
7 0

Answer:

thats 3

Step-by-step explanation:

d:

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For the function q(x) =10 times RootIndex 5 StartRoot x minus 2 EndRoot, what is the inverse function?
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Answer:

C.

Step-by-step explanation:

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The last one since the first one is up 13 and the last one is down 10
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4 0
3 years ago
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II. Let f(x) = 9 – x , g(x) = x2 + x, and h(x) = x – 2. Compute the following:
Neko [114]

Answer:

h(g(x))=x^2+x-2

h(g(f(x))= x^2-19x+88

Step-by-step explanation:

<u>Composite Function</u>

Suppose f(x) and g(x) are real functions, the composite function named (f\circ g)(x) is defined as:

(f\circ g)(x)=f(g(x))

The composite function can be found by substituting g into f.

We are given these functions:

f(x)=9-x

g(x)=x^2+x

h(x)=x-2

Find:

a) h(g(x))

Substituting g into h:

h(g(x))=x^2+x-2

b) h(g(f(x))

First we find g(f(x)):

g(f(x))=(9-x)^2+(9-x)

Operating:

g(f(x))=81-18x+x^2+9-x

Simplifying:

g(f(x))=90-19x+x^2

Now find h(g(f(x)) replacing the above equation into h:

h(g(f(x))= 90-19x+x^2-2

Simplifying and rearranging:

h(g(f(x))= 88-19x+x^2

h(g(f(x))= x^2-19x+88

3 0
3 years ago
Find three consecutive odd integers where the sum of the two largest is seven less than three times the smallest.
Basile [38]

Answer:

<h3>              13, 15, 17</h3>

Step-by-step explanation:

x    - an integer  then  2x + 1 is an odd number  (the smallest one)

consecutive odd numbers increase by 2

so the next odd number (the middle number) is:

2x + 1 + 2 = 2x + 3

and the third (the largest) consecutive is:

2x + 3 + 2 = 2x + 5

the sum of the the two largest numbers is:

2x + 3 + 2x + 5

3 times the smallest number is:  

3(2x + 1)  

the sum of the two largest is seven less than three times the smallest, so:

2x + 3 + 2x + 5 = 3(2x + 1) - 7

4x + 8 = 6x + 3 - 7

   -6x       -6x

-2x + 8 = -4

   -8       -8

-2x  = -12

÷(-2)    ÷(-2)

  x = 6

2x+1 = 2•6+1 = 13

2x+3 = 2•6+3 = 15

2x+5 = 2•6+5 = 17

Check:

2x+3+2x+5 = 15+3+15+5 = 38

38+7 = 45

45÷3 = 15

5 0
3 years ago
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