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AleksandrR [38]
2 years ago
11

A 34-foot tall utility pole is supported by two wires that are anchored 8 feet from the

Mathematics
1 answer:
Andrew [12]2 years ago
7 0

Answer:34.93

Step-by-step explanation:

Using a^2+b^2=c^2we can substitute a and b in which is 34^2+8^2=c^21156+64=c^21220 = c^2Now we need to square both sides√1220 = √c^234.9284983931 ----> 34.9334.93 = cc = 34.93

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What is the volume of this square pyramid?
tatuchka [14]

Answer: 1296 cm³

Step-by-step explanation:

Since, the volume of a square pyramid is,

V = \frac{a^2h}{3}

Where a = side of the square base,

h = height of the pyramid,

By the given diagram,

a = 18 cm,

h = 12 cm,

Hence, the volume of the given pyramid,

V = \frac{18^2\times 12}{3}

= \frac{324\times 12}{3}

=\frac{3888}{3}

=1296 cube cm.

⇒ First option is correct.

5 0
3 years ago
Your hair is
masha68 [24]
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4 0
3 years ago
Pls pls help<br> Show work :)
Natasha2012 [34]

9514 1404 393

Answer:

  31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

  Sin = Opposite/Hypotenuse

  sin(30°) = BE/100

  BE = 100·sin(30°)

Then ...

  Tan = Opposite/Adjacent

  tan(58°) = BE/x

  x = BE/tan(58°) = 100·sin(30°)/tan(58°)

  x ≈ 31.243 . . . . units

_____

<em>Comment on the figure</em>

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.

5 0
2 years ago
In AVWX, x = 5.7 inches, v = 4.5 inches and ZW=114°. Find the area of AVWX, to the
Rus_ich [418]

Answer:

144 i think

Step-by-step explanation:

4 0
2 years ago
Two sides of a triangle measure 25cm and 35cm. which of the following could be the measure of the 3rd side
Bumek [7]
11 cm? Im not that good at this.. If im correct any of those would work
8 0
3 years ago
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