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trasher [3.6K]
3 years ago
11

A rectangle has a perimeter of 50 centimeters. If the width of the rectangle is 10 centimeters, what is its length? step by step

on how you got answer. thank you
Mathematics
2 answers:
Bad White [126]3 years ago
5 0
Perimeter=2Length+2Width \\ P=2(L+W) \\ 50=2(L+10) \\ 25=L+10 \\ L=25-10 \\ \boxed{L=15cm}
Elena-2011 [213]3 years ago
4 0
Ok,   so,, if the p=50, it means that  l+l+w+w=50. (l is length and w is width.)

In simpler form, 2xl+2xw=50. In this case, we know that the width is 10. So,

2xl + 2 x 10= 50
2 x l +20=50.
Now we subtract 20 on both sides to get l alone. 
 2 x l=30
length= 30 divided by 2, or 15
 :-)

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Juli2301 [7.4K]

Answer:

The answer is "The discriminant is positive"

Step-by-step explanation:

When the discriminant is positive there is two real solutions.

When the discriminant is equal to 0, there is one real solution.

When the discriminant is negative, there is no real number solutions.

8 0
2 years ago
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ser-zykov [4K]

Answer:

11. 3^2 • 3^5 < 3^8

12. 3^3 • 3^3 > 3^5

13. Option C.

Step-by-step explanation:

11. Which of the following expressions is true?

A.  4^3• 4^4 = 412

4^3• 4^4 = 4^7 = 16384  ❌

B. 5^2 • 5^3 > 5^5

5^2 • 5^3 = 5^5 ❌

C. 3^2 • 3^5 < 3^8

3^2 • 35 = 315 ✔️

D. 5^2 • 54 = 58

5^2 • 54 = 1350 ❌

12. Which of the following expressions is true?

A. 8^3 • 8^2 < 8^4

8^3 • 8^2 = 8^5 ❌

B. 4^4 • 4^4 = 4^16

4^4 • 4^4 = 4^8 ❌

C. 2^2 • 2^6 < 2^8

2^2 • 2^6 = 2^8 ❌

D. 3^3 • 3^3 > 3^5

3^3 • 3^3 = 3^6 ✔️

13. Write the value of the expression: 3^4/3^4

3^4/3^4 = 1

The correct answer is C. 1 ✔️

4 0
3 years ago
PLEASE HELP PLEASE PLEASE
Phantasy [73]
-2(-2)^4 + 5(-2)^2 - 4

-2(-2)= 4. 4^4= 16

5(-2)= -10. -10^2= 100 - 4= 96

96 + 16= 112

Answer: 112
8 0
3 years ago
In the figure, TP and TS are opposite rays. TQ bisects &lt; RTP.
Ket [755]

Answer:

search-icon-image

Class 9

>>Maths

>>Quadrilaterals

>>Quadrilaterals and Their Various Types

>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2

Question

Bookmark

In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28

0

and ∠QRT=65

0

, then find the values of x and y.

463685

expand

Medium

Solution

verified

Verified by Toppr

Given, PQ⊥PS,PQ∥SR,∠SQR=28

∘

,∠QRT=65

∘

According to the question,

x+∠SQR=∠QRT (Alternate angles as QR is transversal.)

⇒x+28

∘

=65

∘

⇒x=37

∘

Also ∠QSR=x

⇒∠QSR=37

∘

Also ∠QRS+∠QRT=180

∘

(Linear pair)

⇒∠QRS+65

∘

=180

∘

⇒∠QRS=115

∘

Now, ∠P+∠Q+∠R+∠S=360

∘

(Sum of the angles in a quadrilateral.)

⇒90

∘

+65

∘

+115

∘

+∠S=360

∘

⇒270

∘

+y+∠QSR=360

∘

⇒270

∘

+y+37

∘

=360

∘

⇒307

∘

+y=360

∘

⇒y=53

∘

Step-by-step explanation:

please mark me as brainlist please

6 0
2 years ago
This number is equivalent to seventeen and fifty thousandths
Novay_Z [31]
Seventeen and fifty thousandths in stander form is this:
<em><u>17.05</u></em>
5 0
3 years ago
Read 2 more answers
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