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3 years ago

PLS HELp PLS

Mathematics

2 answers:

Nataly [62]3 years ago

6 0

how did you gett such a hard question (yes im asking in an awnser box)

Anestetic [448]3 years ago

4 0

1) Given

2) m∠1 + m∠2 = 90°

3) BD bisects ∠ADC

4) definition of angle bisector

5) definition of congruency

6) m∠1 + m∠3 = 90°

7) ∠1 is complementary to ∠3 (7) definition of complementary

If there is a drop down box, and my answer is not an option, type in the options in the comment box and I will let you know which theorems (or definitions) are the same as my answer.

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The point (-3,3) lies on a circle. What is the length of the radius of this circle if the center is located at (10,6) ?

Amiraneli [1.4K]

The radius is from center to point on a circle.
So your task is count distance between two points: S(10,6) and A(-3,3).
Distance between two points A(x1, y1) and B(x2, y2) count from this formula:
$|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ \hbox{So:} \\ \\ r=|SA|=\sqrt{(-3-10)^2+(3-6)^2}=\sqrt{(-13)^2+(-3)^2}=\sqrt{169+9}= \\ r= \sqrt{178}$

5 0

3 years ago

Read 2 more answers

One hamster weighs 300g less than half the weight of the second. If their combined weight is 1950g,how much does each hamster we

deff fn [24]

Answer: masses are 825 g and 1125 g

Step-by-step explanation: masses of hamsters are x and x+ 300 g.

Total mass is x+(x+300) = 1950

2x = 1650 g and x= 825

3 0

2 years ago

Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad

laila [671]

Answer:

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=17$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.262$

Now we have everything in order to replace into formula (1):

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

4 0

3 years ago

Find the midpoint of the segment with the following endpoints.<br> (-3,6) and (3,0)

Tresset [83]

Answer

(-3, 3)

Step-by-Step

-3-3/2=-6/2= -3
6-0/2= 6/2 = 3

(-3,3)

4 0

3 years ago

Create a numeric vector called age whose elements contain the ages of three people you know, where the names of each element cor

erik [133]

Answer:

age<-c(20,30,40)

names(age)<-c ("ELI", "ALI", "JON")age

## ELI ALI JON

## 20 30 40

Step-by-step explanation:

The above given vector named age consists of three elements. Each element consists of ages of three people, ELI, ALI and JON, such that 20 corresponds to ELI, 30 to ALI and 40 to JON.

8 0

3 years ago