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vaieri [72.5K]
3 years ago
9

Determine any data values that are missing from the table, assuming that the data represent a linear function.

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0

Answer:

c. 14

Step-by-step explanation:

Let the missing y value be y2.

If the data represent a linear function, then:

\frac{6 - 2}{2 - 1} = \frac{y_2 - 6}{4 - 2}

\frac{4}{1} = \frac{y_2 - 6}{2}

4 = \frac{y_2 - 6}{2}

Multiply both sides by 2

4 \times 2 = \frac{y_2 - 6}{2} \times 2

8 = y_2 - 6

Add 6 to both sides

8 + 6 = y_2 - 6 + 6

14 = y_2

The missing value is 14

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a_{0}=3

r=common ratio: 12/6=2; 6/3=2

r=2, a_{n}=2^{n-1}*3

plug in 12 for n:

a_{12}=2^{12-1}*3

a_{12}=2^{11}*3

a_{12}=2048*3

a_{12}=6144

The twelfth term in the sequence is 6144


 




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Find the missing value when given the modulus. <br><br> |48+bi|=50
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Answer:

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Step-by-step explanation:

We have been given the modulus of a complex number which is

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