Answer:
The remainder is 4.
Step-by-step explanation:
Note: This question is not correctly stated. It is therefore correctly restated before answering the question as follows:
When 17 is divided by k; where k is a positive integer less than 17, the remainder is 3. What is the remainder when the sum of the possible values of k is divided by 17?
The explanation of the answer is now given as follows:
Since k < 17, it implies that the possible values of k must be from between 1 and 16 inclusive.
Between 1 and 16, only 7 or 14 will give a remainder of 3 when either of them is used to divide 17. Therefore, 7 and 14 are the possible values of k.
Therefore, we have:
Sum of the possible values of k = 7 + 14 = 21
Also, we have:
Sum of the possible values of k divided by 17 = 21 / 17 = 1 with a remainder of 4.
Therefore, the remainder is 4 when the sum of the possible values of k is divided by 17.
Answer: 90.82%
Step-by-step explanation:
Given : The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal .
Mean : 
Standard deviation: 
Let X be the random variable that represents the amount of soda in bottles.
Formula for z-score : 
Z-score for 16 oz: 
Using the standard normal z-distribution table , the probability that the soda bottles that contain more than the 16 OZ is given by :_
Hence, the percentage of the soda bottles that contain more than the 16 OZ advertised is 90.82% .
<span>proportional function equation is <span>y = kx
x = age
y = dollars
k = amount per
Q18
I believe father side would be y = 5x
mother side would be y = 2x
Q19
at 16 they would receive 80 from father side
and receive 32 from mother side
which is a difference of 48dollars.
</span></span>
49.95 Would be the Registration fee because it is a number by itself, 24.72m would be the monthly payment because it is being multiplied by m, m being months.
No, for example 8-1. If you do the Commutative property, it would be 1-8; which would be a negative number. Associate property is basically the same thing; so no, you can't.
