Answer:
The ratio of the number of Lisa’s stickers to the number of John’s stickers is 3/2
Step-by-step explanation:
Step 1
Let
x ----> the number of stickers that Lisa has
y ----> the number of stickers that John has
we know that
------> equation A
----> equation B
Solve the system by substitution
Substitute equation B in equation A and solve for y

Find the value of x
-----> 
therefore
Lisa has 36 stickers and John has 24 stickers
Step 2
Find the ratio of the number of Lisa’s stickers to the number of John’s stickers
so
x/y
substitute

Answer:
16
Step-by-step explanation:
grater than 13 less than 20
14,15,16,17,18,19
6 ones
16
Answer:
26
Step-by-step explanation:
Put 10 in the formula where x is, then do the arithmetic.
y = 10(1.1^10) ≈ 10(2.5937) ≈ 26
Mark will be running 26 miles per day 10 weeks from now.
Answer:
15 feet
Step-by-step explanation:
It is given that Quadrilateral ABCD is similar to Quadrilateral EFGH. This means that the corresponding sides of these two quadrilateral will be in the same proportion.
i.e.
Ratio of two corresponding sides would be the same. We are given longest three sides of ABCD and shortest two sides of EFGH. Let the 4th sides of ABCD i.e. the shortest side be x.
So, the ratio of the shortest sides of two quadrilaterals would be the same as the ratio of second shortest sides.
So,

So, the 4th side on quadrilateral ABCD would be 15 feet. None of the options match with the answer.
Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C