Step-by-step explanation:
$20/hr carpenter pay
$25/hr blacksmith pay
Let c = hours working carpentry
Let b = hours working as blacksmith
c + b = 30 {equation 1}
20c + 25b = 690 {equation 2}
In equation 1 solve for one variable in terms of the other.
c = 30-b
Substitute that into equation 2:
20(30-b) + 25b = 690
600 - 20b + 25b = 690
5b = 90
b = 90/5
b = 18 hours working as a blacksmith
c = 30-b = 30-18 = 12 hours as a carpenter
Answer:
Cost of one roll of plain wrapping: 
Cost of one roll of holiday wrapping paper: 
Step-by-step explanation:
Let be "p" the cost in dollars of one roll of plain wrapping paper and "h" the cost in dollars of one roll of holiday wrapping paper.
Based on the information given, we can set up this system of equations:

In order to solve it, we can use the Substitution method. The steps are:
1. Solve for "p" from the first equation:

2. Substitute the above into the second equation and solve for "h":
3. Substitute the value of "h" into
:

Working:
$5.29 + ((2/3) x 3.59) + ((4/3) x 4.79)
= $14.07 (to 2d.p.)
So, she estimated correctly that she will spend around $14 on the flowers but slightly more than $14, so I don't really know if you should say that she estimated correctly or not
Answer:
Domain of a geometric or arithmetic sequence is the counting numbers unless otherwise noted.