Answer:
f(- 3) = 18
Step-by-step explanation:
To evaluate f(- 3) substitute x = - 3 into f(x)
f(- 3) = (- 3)² - 2(- 3) + 3 = 9 + 6 + 3 = 18
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Answer:
d
Step-by-step explanation:
2x+3x-9-1
x
<em><u>
</u></em>
Answer:
The answer is 1.
Step-by-step explanation:
Answer:
2. This is only true when x=-3.
3. This is only true when x=3.
4. This is only true when x=12.
5. This has no solution.
6. This has an infinite number of solutions.
