Answer:
Part A: Angle R is not a right angle.
Part B; Angle GRT' is a right angle.
Step-by-step explanation:
Part A:
From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).
Slope formula

The product of slopes of two perpendicular lines is -1.
Slope of GR is

Slope of RT is

Product of slopes of GR and RT is

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.
Part B:
If vertex T translated by rule

Then the coordinates of T' are


Slope of RT' is

Product of slopes of GR and RT' is

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.
Parallel graphs have the same slope. perpendicular has opposite reciprocal slopes. These equations have slopes of -2/5 and 25 so they are neither.
Answer:
A: f(x)=10cos(2π/5 x)+10
Step-by-step explanation:
The coefficient of x in the cosine argument of the function will be 2π/period. Since the period is 5, the coefficient is 2π/5. This observation eliminates choices B and C.
The description "not a reflection of the parent function over the x-axis" means the multiplier of the cosine function is not negative, eliminating choice D.
The remaining choice A matches the description.
I think it is D. it translates into .875 which is .88