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4vir4ik [10]
3 years ago
5

Can someone help me with this :( , it’s similar triangles btw

Mathematics
2 answers:
OverLord2011 [107]3 years ago
8 0

<em><u>HOPE </u></em><em><u>THIS </u></em><em><u>HELPS </u></em><em><u>YOU</u></em>

I KNOW THAT THESE TRIANGLES ARE SIMILAR BY THE WAY...

dem82 [27]3 years ago
7 0

Answer:

The triangles are propotional

Step-by-step explanation:

<u>FH</u> = <u>45</u> = <u>5</u>

BC 27 3

<u>GH</u> = <u>22.5</u> = <u>5</u>

BD 13.5 3

<u>GF</u> = <u>30</u> = <u>10</u> = <u>5</u>

CD 18 6 3

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Six less than the product of four and a number x. Can someone Help PLS <br>​
Ann [662]

Answer:

4x - 6

Step-by-step explanation:

6 less is -6

product of four and a number x is 4x

3 0
2 years ago
Q5.Jumbo is standing on top of a cliff looking at a speed boat out at sea.The vertical of the cliff from the base (sea level) to
Leni [432]

Answer:

A) 150 m

B) 180.28 m

Step-by-step explanation:

A) In order to find the horizontal distance from the base of the cliff to the speed boat, use the Pythagorean theorem to calculate the length of the missing side.

We are told that one of the sides is 80 m and the hypotenuse is 170 m. Therefore,

  • a² + b² = c²
  • (80)² + b² = (170)²
  • b² = 170² - 80²
  • b² = 22500
  • b = 150

The horizontal distance between the base of the cliff and the boat is 150 m.

B) Now, the side that was 80 m is now 100 m (includes the height that the helicopter is above Jumbo). The horizontal distance remains the same, 150 m, but the hypotenuse is different. Solving for the hypotenuse will give us the distance between the helicopter and the speed boat.

  • (100)² + (150)² = c²
  • 32500 = c²
  • 180.28 = c

The distance between the helicopter and the speed boat is 180.28 m.

8 0
3 years ago
What is the answer to b?
Mama L [17]

Answer:

43

Step-by-step explanation:

3 0
3 years ago
Explain how you know 21/30 is greater than two thirds
NemiM [27]
For this question you should know that 2/3 is equal to 20/30 so now you can see that 21/30 is greater than 20/30 :)))
i hope this is helpful 
have a nice day 
7 0
3 years ago
Read 2 more answers
9. Reflect figure OPQR over the x-axis.
erastovalidia [21]

Answer:

9) P' will be at (-3, -6)

10) T' will be at (0, -1)

11) Quadrant IV

Step-by-step explanation:

9) point P is 3 units away from the y-axis and 6 units away from the x-axis; after reflecting over x-axis it will still be the same distances away from each axis but will be in a different quadrant

10) T is at (5, 6); if translated it will be at (5-5 , 6-7) or (0, -1)

11) a point or shape moves to a new quadrant every 90 degrees

5 0
3 years ago
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