No. 6r is 6 multiplied by r so in order to get r, you will need to divide both sides by 6 in the first equation so r should =12
Parenthesis indicate which part of the equation is to be done first, see PEMDAS. For example, 3(5-2)-4=5, but 3*5-(2-4)=17
Firstly, order the two data set from smallest to largest as shown in diagram below
The value of median, Q2 is the 5th value of both set
The value of Q1 and Q3 is the first and third quarter of the set
The range of data set one is 5-2=3 and of set two is 12-1=11
The interquartile range of set one is 5 - 2 = 3
The interquartile range of set two is 5 - 1.5 = 3.5
The box plot is not symmetrical for either data set
Answer:
w = -7
Step-by-step explanation:
6= 20 + w/2
-20
-14= w/2
÷2
-7= w
Answer: 9m^4- 30m^3 +37m^2 - 20m + 4
Step-by-step explanation:
(3m^2 -5m +2)^2 is the same as (3m^2 -5m +2)(3m^2 -5m +2)
Now apply the distributive property 3 times to solve.
3m^2(3m^2 -5m + 2) = 9m^4 - 15m^2 + 6m^2
-5m(3m^2 -5m+2) = -15m^3 +25m^2 -10m
2(3m^2 -5m +2) = 6m^2 - 10m + 4
Now add the solutions
(9m^4 - 15^2 + 6m^2) (-15m^3 + 25m^2 -10m)(6m^2 -10m +4) =
9m^4- 30m^3 +37m^2 - 20m + 4