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4vir4ik [10]
2 years ago
5

Can someone help me with this :( , it’s similar triangles btw

Mathematics
2 answers:
OverLord2011 [107]2 years ago
8 0

<em><u>HOPE </u></em><em><u>THIS </u></em><em><u>HELPS </u></em><em><u>YOU</u></em>

I KNOW THAT THESE TRIANGLES ARE SIMILAR BY THE WAY...

dem82 [27]2 years ago
7 0

Answer:

The triangles are propotional

Step-by-step explanation:

<u>FH</u> = <u>45</u> = <u>5</u>

BC 27 3

<u>GH</u> = <u>22.5</u> = <u>5</u>

BD 13.5 3

<u>GF</u> = <u>30</u> = <u>10</u> = <u>5</u>

CD 18 6 3

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3 years ago
Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4
gtnhenbr [62]

Answer:

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Step-by-step explanation:

We need to simplify the expression (6^{-2})(3^{-3})(3*6)^4

Solving:

(6^{-2})(3^{-3})(3*6)^4

Applying exponent rule: a^{-m}=\frac{1}{a^m}

=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\

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Factors of 6=2\times 3

Replacing terms with factors

=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\

Using exponent rule: (a^m)^n=a^{m\times n}

=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}

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=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}

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=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108

So, simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

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