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Olin [163]
3 years ago
8

What is the inverse function of f(x)= 4- x/6

Mathematics
1 answer:
Westkost [7]3 years ago
6 0

Answer:

f^{-1}(x) = 6(4-x) = 24-6x

Step-by-step explanation:

Let y=f(x) and swap x and y:

x = 4 - \frac{y}{6}

Then, rearranging for y:

x+\frac{y}{6} = 4

\frac{y}{6}= 4-x

y= 6(4-x) = 24-6x

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The 50th term of a sequence is 102 with a difference of 2. Find the first term.
stich3 [128]
Look here https://www.varsitytutors.com/algebra_1-help/how-to-find-the-nth-term-of-an-arithmetic-sequence
3 0
3 years ago
Based on its degree, what kind of polynomial is this <br><br> h(x)= -6x^3+2x-5
Lelechka [254]

Answer:

cubic polynomial

Step-by-step explanation:

Given polynomial is \[h(x)=-6x^{3}+2x-5\]

A polynomial of degree 1 is a linear polynomial.

A polynomial of degree 2 is a quadratic polynomial.

A polynomial of degree 3 is a cubic polynomial.

In this case the exponent with the maximum value in the polynomial is 3.

Hence the degree of the polynomial h(x) is 3.

Hence the given polynomial is a cubic polynomial.

7 0
3 years ago
The graph below shows a quadratic function f(x) and an absolute value function g(x)
Sophie [7]

Answer:

The x-values that are approximate solution of the equation f(x) = g(x) are x_{1} \approx -3.5 and x_{2}\approx 5, respectively.

Step-by-step explanation:

From graph we infer that the x-values that represents a solution to the system of equations corresponds to those values of x in which both functions coincide. As we see, there are two x-values for f(x) = g(x), which are described below:

x_{1} \approx -3.5 and x_{2}\approx 5

The x-values that are approximate solution of the equation f(x) = g(x) are x_{1} \approx -3.5 and x_{2}\approx 5, respectively.

6 0
3 years ago
Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2
evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}

Step # 1 : Swap the first and second matrix rows,

\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}

Step # 2 : Cancel leading coefficient in row 2 through R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1,

\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0
3 years ago
Which decimal is equivalent to 25/6?
Marysya12 [62]

Answer:

4.166666667

Step-by-step explanation:

5 0
3 years ago
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