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yaroslaw [1]
4 years ago
6

What is the value of x? Round your answer to the nearest tenth if necessary.

Mathematics
1 answer:
Lemur [1.5K]4 years ago
7 0
5^2+8^2=X^2
25+64=X^2
89=X^2
SQUARE ROOT OF 89=X
X=9.4
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A is the correct answer
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A rectangular sticker has an area of 50 square centimeters. Its perimeter is 30 centimeters. What are the dimensions of the stic
Nata [24]

Length + width = 1/2 the perimeter:30/2 = 15

Area = length x width

List the factors of 50: 1, 2, 5, 10, 25, 50.

Find the two factors that when added together equal 15:

Dimensions are 5 cm by 10 cm.

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2 years ago
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What is 49 divided by 3 plus 87
ozzi

Answer: 103.3

Step-by-step explanation:

Divide 49/3 and u get 16.3333333333. Then add 16.3333333333 and 87 and get 103.333333333. Round 103.333333333 to the nearest tenth and get 103.3

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3 years ago
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One integer is 5 less than another and their product is 84. Find the integers.
andrezito [222]

The first integer is going to be x and the second one is going to be y.

We now turn the clues into equations:

x = y - 5

xy = 84

The substitution method:

(y - 5)y = 84

y^2 - 5y - 84 = 0

(y+7)(y-12) = 0

y = -7, 12.

If y = -7, then x = -12.

If y = 12, then x = 7

5 0
3 years ago
Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra
bearhunter [10]

Answer:

\frac{dh}{dt}=-\frac{1}{2\pi}cm/min

Step-by-step explanation:

From similar triangles, see diagram in attachment

\frac{r}{4}=\frac{h}{16}


We solve for r to obtain,


r=\frac{h}{4}


The formula for calculating the volume of a cone is

V=\frac{1}{3}\pi r^2h


We substitute the value of r=\frac{h}{4} to obtain,


V=\frac{1}{3}\pi (\frac{h}{4})^2h


This implies that,

V=\frac{1}{48}\pi h^3


We now differentiate both sides with respect to t to get,

\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}


We were given that water is drained out of the tank at a rate of 2cm^3/min


This implies that \frac{dV}{dt}=-2cm^3/min.


Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means h=8cm.


We substitute this values to obtain,


-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}


\Rightarrow -2=4\pi \frac{dh}{dt}


\Rightarrow -1=2\pi \frac{dh}{dt}


\frac{dh}{dt}=-\frac{1}{2\pi}






3 0
4 years ago
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