Answer:
x=70
Step-by-step explanation:
Answer:
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
Step-by-step explanation:
Given:
Length of drive way at garage door = 12 feet
Length of drive way at street = 20 feet
Length of total driveway = 18 feet
Find:
Amount of Winter sealer for 2 coats[in square feet]
Computation:
Amount of Winter sealer for 2 coats[in square feet] = 2[Area of trapezoid]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(Sum of parallel side)(Height)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(12 + 20)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(32)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 32 x 18
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
There are exactly 0.499999 quarts in 1 <span>pint.</span>
That is mathematically impossible but maybe the other way around is possible. If you did 8765 divided by 5 you would get 1753. I hope this is what you want :)
Answer:
The correct options are:
Interquartile ranges are not significantly impacted by outliers.
Lower and upper quartiles are needed to find the interquartile range.
The data values should be listed in order before trying to find the interquartile range.
The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range.
The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
