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MA_775_DIABLO [31]
3 years ago
11

How does human evolution or natural selection relate to the susceptibility of disease?

Biology
2 answers:
meriva3 years ago
5 0
Quote from the internet:

"Human evolution known to be a process in which species adapt to certain conditions of life, and in the battle of life and death, they are forced to become stronger in order to survive in this world. Diseases have always been present during the evolution, acting themselves as a natural selectors - the weaker organisms get sick and die. Not just humans, but all species have to establish a great protecting mechanism in order to survive. That is how our bodies are built, to be able to withstand and survive in the conditions we live in, and that is why our immune system has to be taken care of. "

Basically this is saying that through evolution and natural selection, a population will be able to defend itself against a common disease.

Example: those who are heterozygous for sickle cell anemia are immune to malaria, a disease that is common in places like west Africa and has is very deadly


Lera25 [3.4K]3 years ago
4 0
Reproduction and growing.
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Why are plants unable to grow at the bottom of lakes?
Tpy6a [65]

Answer:

Sunlight does not reach the bottom.

Explanation:

It honestly depends on how deep, Coral is more suited for shallow waters, where sunlight reaches.

5 0
4 years ago
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Point where crossing over takes place between chromatids of the homologous chromosomes during prophase 1
Free_Kalibri [48]

Answer:

Crossing over occurs during prophase I of meiosis before tetrads are aligned along the equator in metaphase I.

Explanation:

When chromatids "cross over," homologous chromosomes trade pieces of genetic material, resulting in novel combinations of alleles, though the same genes are still present. Crossing over occurs during prophase I of meiosis before tetrads are aligned along the equator in metaphase I.

3 0
2 years ago
Before a captive breeding program and subsequent reintroduction of the black-footed ferret it is believed that their total popul
irga5000 [103]

Answer:

a) 99.93%

b) 99.98%

Explanation:

Given that:

Total population size was only around 18 individuals ( for  black-footed ferret)

If the annual survival rate in the wild was 0.4%.

a)

What is the probability that all 18 would have died in a single year?

To find that; we multiply the annual survival rate in the wild with the total population; which is:

(0.4%×18) = 0.072%

Then; we subtract it from a total of 100% in order to determine the probability that all 18 would have died in a single year.

= (100.00% - 0.072%)

= 99.93%

b)

What is the probability that all 18 would have died in a single year if canine distemper was present?

Given that;

Because of the presence of canine distemper disease, the annual mortality rate might have been as high as 0.89.

To determine the probability; we have:

1 - Annual mortality rate = annual survival rate

1 - 0.89 = 0.11 %

Therefore, 0.11% of 18 individuals = (0.0011 × 18)

= 0.0198%

Probability that all 18 would have died in a single year if canine distemper was present = 100 - probability of annual survival rate

= (100 - 0.0198)%

= 99.98%

7 0
3 years ago
Many organisms in the deep sea live in conditions where resources are rare and populations are small and sparse. Many of those s
asambeis [7]

Answer:

<em>The correct option is A)  Reproductive assurance: any individual of the same species is a potential mate.</em>

Explanation:

A hermaphrodite can be described as an organism that is capable to produce gametes associated with both the male and female sexes. It has a complete or partial reproductive organ.

In the deep sea, biodiversity is scarce. There are limited amounts of organisms present. Hence, to have a reproductive assurance, the organisms present in the deep sea are mostly hermaphrodite. Hence, they will be able to mate with any organism of the same species.

4 0
3 years ago
.
horsena [70]

Answer:

C is correct ans

Explanation:

Mark my answer as brainliest and thank me

5 0
3 years ago
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