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Evgen [1.6K]
3 years ago
9

Paulie ordered 250 pens and 250 pencils to sell for a theatre club fundraiser. The pens cost 11 cents more than the pencils. If

Paulie's total order costs $42.50, find the cost of each pen and pencil
Mathematics
1 answer:
I am Lyosha [343]3 years ago
5 0

Answer:

Pen: $0.03

Pencil: $0.14

Step-by-step explanation:

let x be the cost of 1 pencil

this means that the cost of a pen would be x + 0.11

Since she bought 250 pens and 250 pencils, that would be:

250x + 250(x + 0.11) = 42.5

solve:

250x + 250(x + 0.11) = 42.5\\250x + 250x +27.5=42.5\\500x = 15\\x = 0.03

This means that the cost of a pencil is $0.03 and the cost of a pen is 11 cents greater, so $0.14.

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Find an explicit rule for the nth term of the sequence.
exis [7]

Answer:

(a) The ONLY explicit rule for the nth term of the sequence is a_n = 7  \times (-1)^{n-1}\\.

Step-by-step explanation:

Here, the given sequence is 7, -7, 7, -7, ...

The first term = 7, Second term = -7, Third term =-7 and so on..

Now check the given sequence for each given formula, we get:

(1)  a_n = 7  \times (-1)^{n-1}\\

Now, for n = 1 : a_1 = 7  \times (-1)^{1-1}\\

                                       = 7 \times (-1)^0 =  7 \times 1 = 7 \implies a_1 = 7

Similarly, for, n = 2:  a_2 = 7  \times (-1)^{2-1}\\

                                       = 7 \times (-1)^1 =  7 \times (-1) = -7 \implies a_2 = -7

Hence, the given formula satisfies the given sequence.

(2)  a_n = 7  \times (-1)^{n}\\

Now, for n = 1 : a_1 = 7  \times (-1)^{1}\\

                                       = 7 \times (-1)^1 =  7 \times (-1) = -7 \implies a_1 = -7

But, First term = 7

Hence, the given formula DO NOT satisfy the given sequence.

(3)  a_n = 7  \times (1)^{n-1}\\

Now, for n = 1 : a_1 = 7  \times (1)^{1-1}\\

                                       = 7 \times (1)^0 =  7 \times 1 = 7 \implies a_1 = 7

Similarly, for, n = 2:  a_2 = 7  \times (1)^{2-1}\\

                                       = 7 \times (1)^1 =  7 \times (1) = 7 \implies a_2 = 7

But, Second term = -7

Hence, the given formula DO NOT satisfy the given sequence.

(4) a_n = 7  \times (1)^{n+1}\\

Now, for n = 1 : a_1 = 7  \times (1)^{1+1}\\

                                       = 7 \times (1)^2 =  7 \times 1 = 7 \implies a_1 = 7

Similarly, for, n = 2:  a_2 = 7  \times (1)^{2+1}\\

                                       = 7 \times (1)^3 =  7 \times (1) = 7 \implies a_2 = 7

But, Second term = -7

Hence, the given formula DO NOT satisfy the given sequence.

So, the ONLY explicit rule for the nth term of the sequence is a_n = 7  \times (-1)^{n-1}\\.

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