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Amiraneli [1.4K]
3 years ago
11

Which of the following statements shows the inverse property of addition?

Mathematics
1 answer:
Kaylis [27]3 years ago
3 0

Answer:

a+(-a)=0

Step-by-step explanation:

Let a\in \mathbb R, that is a be any real number.

The inverse property of addition says that, the sum of a number a and its additive inverse -a gives the identity element of addition which is zero.

That is :

a+(-a)=0

We can rewrite this as -a+a=0

From the above options, we have the correct answer to be the first choice

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If x = 0 is 1990, x = 1 is 1991, then 1998 is represented by x = 8. Substitute this value of x into the quadratic equation to find y:
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Graph the inequality. x < 2
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Step-by-step explanation:

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$10,788 per dozen, find for EACH computer (a) dollar markup, (b) percent markup on cost, and (c) percent markup on selling price
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3 years ago
Can someone explain how u can write a percent in simplest form?
mash [69]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Number two please <br> ASAP
miv72 [106K]

The solutions for -5 +2x^{2} = -6x is option 3. x= \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .

Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of ax^{2} +bx +c =0.

So -5 +2x^{2} = -6x becomes 2x^{2} +6x-5=0.

The value of a is the coefficient of the x^{2} term, the value of b is the coefficient of x term and c is the coefficient of the constant term.

Comparing the above equation to ax^{2} +bx +c =0, we get a = 2, b = 6, and c=-5.

We have the formula x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

By substituting the known values, we get

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} =\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)}.

\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)} = \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .

This is the third option.

8 0
4 years ago
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