A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height
in feet t seconds after launch is given by s=-16t2+v0t. Find the time(s) that the projectile will (a) reach a height of 288 ft and (b) return to the ground when v0=144 feet per second.
1 answer:
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Answer:
1) at ( 0,0) : y = x/2. at(-3-1) : y = -1. at(-3,3) : y = 2x +9
2) DNE ( does not exist )
Step-by-step explanation:
The general equation of tangent line
y - y1 = m( x - x1 )
attached below is the detailed solution on how i derived the answers above
Answer:
y =
Step-by-step explanation:
The equation for a linear graph is usually written in the following format...
y = mx + b
Where m would be the slope, usually referring to rise over run and b would be the y-intercept (where the line crosses the y-axis). From the graph, we can see that the line crosses the y-axis at point 3 so b would be 3. The graph also shows us that for every 1 value that the line rises it moves to the right 2 values. Therefore, the slope would be 1/2. Using these values we can create the following equation...
y =