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Sholpan [36]
3 years ago
10

A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height

in feet t seconds after launch is given by s=-16t2+v0t. Find the time(s) that the projectile will (a) reach a height of 288 ft and (b) return to the ground when v0=144 feet per second.

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Step-by-step explanation:

I've posted solutions in the picture. Rather the ways to solve them. Check and find answers on your own.

Also, I've not solved the problem by differential calculus. You can, obviously, if you're interested. Use it for ease and for tougher equations.

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Read 2 more answers
B(n)=1 (-2)^n-1<br> What is the 4th term in the sequence
zzz [600]

Answer:

The fourth term of the sequence B(4) =-8

The sequence is 1,-2,4,-8...

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the sequence

     B(n) = 1(-2)ⁿ⁻¹

Put n=1

    B(1) = 1(-2)¹⁻¹ = 2⁰ =1

Put n=2

   B(2) = 1(-2)²⁻¹ = (-2)¹ =-2

Put n=3

  B(3) =1(-2)³⁻¹ = (-2)² =4

Put n=4

B(4) = 1(-2)⁴⁻¹ =(-2)³ =-8

The sequence

1,-2,4,-8...

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3 years ago
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